It would be an obtuse angle :)
Answer:
Step-by-step explanation:
Question 2
As far as I can see, you got it right. The general transformation for 90 ccw is
(x,y) ===> (-y, x)
What that means is for the x you put in -y changing the sign to the opposite and for the y you put in x and this time you leave the sign alone . The transformation is shown in the left hand diagram.
The two tables are shown below.
Original
The transformed table is
- (-4,1)
- (-2,1)
- (-2,3)
- (-5,3)
- (-4,1) This is just to let the program know to close the figure For some reason this did not have lines and if I delete it and put the lines in, I won't be able to upload the new diagram.
===========
Four
This one transforms from (x,y) to (-x,-y) which means where you see an x, you put a - x and where you see a y, you put a minus y. It is the middle frame.
Original
- (-4,3)
- (0,3)
- (-2,0)
- (-4,3) Here again, this is just to close the figure.
The transformed figure in red I think is
- (4,-3)
- (0,-3
- (2,0)
- (4,-3) And this closes the figure as well.
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Six
The diagram is on the right
Reflection about the y axis. Here the transformation is (x,y) ====> (-x,y) notice the ys don't change.
There is no closure.
Reflection
6m3 - 16m2 + 15m - 40<span> Simplify —————————————————————
2m2 + 5
</span>Checking for a perfect cube :
<span> 4.1 </span> <span> 6m3 - 16m2 + 15m - 40</span> is not a perfect cube
Trying to factor by pulling out :
<span> 4.2 </span> Factoring: <span> 6m3 - 16m2 + 15m - 40</span>
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 15m - 40
Group 2: <span> -16m2 + 6m3</span>
Pull out from each group separately :
Group 1: (3m - 8) • (5)
Group 2: <span> (3m - 8) • (2m2)</span>
-------------------
Add up the two groups :
<span> (3m - 8) • </span><span> (2m2 + 5)</span>
<span>Which is the desired factorization</span>
<span>3m-8 is the answer</span>
The answer to the problem is 17
Answer:
76
Step-by-step explanation:
if the number after period is bigger than 5.. then it's about the number higher than the number befor the period
sorry if u have trouble understanding what I said I'm really not good at explaining:)