Question

Solve the system of equations.

Answer 1

If you put them together, +2.5y and -2.5y neutralize themselves while 5x and 3x become 8x.

2.5y + 3x = 27

5x – 2.5y = 5

8x = 32

x = 4

2.5y + 3x4 = 27

2.5y + 12 = 27

2.5y = 27-12

2.5y = 15

y = 15/2.5

y = 6

X = 4

Y = 6

Answer 2

Answer:

The result of adding the two equations is:

$8x=32$

The solution to the system is:

(4, 6).

Step-by-step explanation:

We have the system of equations:

$\left\{ \begin{array} \ 2.5y+3x=27 \\ 5x-2.5y=5 \end{array}$

We can solve by elimination. If we add the two equations together, we acquire:

$(2.5y+3x)+(5x-2.5y)=(27+5)$

Simplifying gives:

$(2.5y-2.5y)+(3x+5x)=(32)$

Combine like terms. So, when they are added together, we acquire:

$8x=32$

We can solve for x. Divide both sides by 8:

$x=4$

Now, we can solve for y. We can use either one of the two equations. Let’s use the first one:

$2.5y+3x=27$

Substitute 4 for x and solve for y:

$2.5y+3(4)=27$

$2.5y+12=27$

Subtract 12 from both sides:

$2.5y=15$

Divide both sides by 2.5. So, the value of y is:

$y=6$

Hence, our solution is:

(4, 6).