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8_murik_8 [283]
3 years ago
12

( image attached) plz help 50 point test ASAP(:

Mathematics
2 answers:
Volgvan3 years ago
7 0

Answer:

vertical line as all x's are 3

Shtirlitz [24]3 years ago
4 0
A vertical line i believe since x is constant
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Answer: 1.18 OR 0.18

Step-by-step explanation:

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Which situation CANNOT be represented by this equation?
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Answer:

1

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Cell Phone Company A charges $20 each month plus $0.03 per text. Cell Phone Company B charges $5 each month plus $0.07 per text.
Ymorist [56]
Cost of company A=monthlyfee+text=20+0.03t where t=number of texts
A=20+0.03t

company b is monthlyfee+texts=5+0.07t
B=5+0.07t



1.
c=20+0.03t
c=5+0.07t
using c for cost is confusing because we can't tell which is for which company



2.

equal, means the costs are equal so
20+0.03t=5+0.07t
minus 5 from both sides
15+0.03t=0.07t
minus 0.03t from both sides
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4 0
3 years ago
Read 2 more answers
Which statement best describes the polynomial 2x+8?
AleksandrR [38]
A
It is a first degree polynomial (aka linear because its highest power is 1) and it has two terms (2x and 8)
It does not have eight terms and is not a monomial (one term ie 3x^2)
8 0
3 years ago
A concert hall has 8,000 seats and two categories of ticket prices, $29 and $34. Assume that all seats in each category can be s
Greeley [361]

Using a system of equations, it is found that:

  • For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
  • For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
  • For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

--------------------

The variables of the system are:

  • x, which is the number of $29 tickets sold.
  • y, which is the number of $34 tickets sold.

Total of 8,000 seats, all can be sold, thus:

x + y = 8000 \rightarrow x = 8000 - y

--------------------

For a profit of $255,000, we have that:

29x + 34y = 255000

29(8000 - y) + 34y = 255000

5y = 23000

y = \frac{23000}{5}

y = 4600

x = 8000 - 4600 = 3400

For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.

--------------------

For a profit of $271,000, we have that:

29x + 34y = 271000

29(8000 - y) + 34y = 271000

5y = 39000

y = \frac{39000}{5}

y = 7800

x = 8000 - 7800= 200

For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.

--------------------

For a profit of $235,000, we have that:

29x + 34y = 235000

29(8000 - y) + 34y = 235000

5y = 3000

y = \frac{3000}{5}

y = 600

x = 8000 - 600 = 7400

For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

A similar problem is given at brainly.com/question/22826010

3 0
3 years ago
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