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8_murik_8 [283]
2 years ago
12

( image attached) plz help 50 point test ASAP(:

Mathematics
2 answers:
Volgvan2 years ago
7 0

Answer:

vertical line as all x's are 3

Shtirlitz [24]2 years ago
4 0
A vertical line i believe since x is constant
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The supplement of an angle is 3 times the complement of an angle.
-Dominant- [34]
Let’s says that x is the measure of the angle. X and it’s supplement are equal to 180. X and it’s complement are equal to 90. The supplement is s and the complement is c. S is times c which is the same as 3c.

3c + x = 180

C+x = 90
X = 90 - c

3c + 90 - c = 180
2c = 90
C = 45

The complement of. 45 degree angle is 45 degrees.

The angle is 45 degrees.
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=2%20%2B%20%28%20-%203%29%20%20%20%5E%7B2%7D%20" id="TexFormula1" title="2 + ( - 3) ^{2} " al
Troyanec [42]

Answer:

11

Step-by-step explanation:

2 + ( - 3) ^{2}  \\  \\  = 2 + 9 \\  \\  = 11

4 0
2 years ago
Read 2 more answers
What is the solution if the inequality shown below? a+2&lt;-10​
daser333 [38]

Answer:

a < -12

Step-by-step explanation:

Isolate the variable, a. Treat the < as a equal sign, what you do to one side, you do to the other. Subtract 2 from both sides:

a + 2 < -10

a + 2 (-2) < -10 (-2)

Simplify:

a < -10 - 2

a < -12

a < -12 is your answer.

~

6 0
2 years ago
Read 2 more answers
Write a word problem for which you would use the equation 2/5x + 6 = 56
velikii [3]

Answer:

Isha is at an arcade. There is a base fee of $6 to enter the game room. Every game costs $0.4 or 40 cents to play. If Isha ends up spending $56 at the arcade, how many games did she play?

An explanation:

The base fee of $6 represents the constant 6 in the equation. Every game costs $0.4, which equals 2/5.

Hope this helps! If you don't like this one I might be able to think of another one :)

7 0
3 years ago
Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = xyi + 5zj + 7yk
REY [17]

By Stokes' theorem,

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

where S is the surface with C as its boundary. The curl is

\nabla\times\vec F(x,y,z)=2\,\vec\imath-x\,\vec k

Parameterize S by

\vec\sigma(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(8-u\cos v)\,\vec k

with 0\le u\le9 and 0\le v\le2\pi. Then take the normal vector to S to be

\vec\sigma_u\times\vec\sigma_v=u\,\vec\imath+u\,\vec k

Then the line integral is equal to the surface integral,

\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9(2\,\vec\imath-u\cos v\,\vec k)\cdot(u\,\vec\imath+u\,\vec k)\,\mathrm du\,\mathrm dv

\displaystyle=\int_0^{2\pi}\int_0^9(2u-u^2\cos v)\,\mathrm du\,\mathrm dv=\boxed{162\pi}

7 0
2 years ago
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