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2 years ago

What is the answer for -4 (12)= what is the answer

Mathematics

2 answers:

Naddik [55]2 years ago

8 0

Answer:

-48

Step-by-step explanation:

12 x 4= 48 just add negative sign to 48.

Hope this helps :3

bulgar [2K]2 years ago

6 0

Answer:

-4(12) = -48

Step-by-step explanation:

Negative stay negative and 4 multiply by 12 is 48 from the multiplication table, therefore -4 multiply by 12 is -48.

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Evaluate the expression 5×5^2÷5-6

Anika [276]

Step-by-step explanation:

according to BODMAS

5×5^2÷5-6

5^2=25

5×25÷5-6

5×5-6

25-6=19

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2 years ago

Is these correct bro

iren [92.7K]

Answer:

yes

Step-by-step explanation:

if my eyes are good then yes

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3 years ago

Which expression is equivalent to one over 3p + 15?

Dafna1 [17]

3p + 15 = 3(p + 5) (distributive property)

answer
3(p + 5)

6 0

3 years ago

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Use the discriminant to predict the nature of the solutions to the equation 4x-3x²=10. Then, solve the equation.

AleksandrR [38]

Answer:

Two imaginary solutions:

x₁= $\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

x₂ = $\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

Step-by-step explanation:

When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.

The discriminant gives us information on how the solutions of the equations will be.

If the discriminant is zero, the equation will have only one solution and it will be real
If the discriminant is greater than zero, then the equation will have two solutions and they both will be real.
If the discriminant is less than zero, then the equation will have two imaginary solutions (in the complex numbers)

So now we will work with the equation given: 4x - 3x² = 10

First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0

So:

4x - 3x² = 10

-3x² + 4x - 10 = 0 will be our equation

with this information we have that a = -3 b = 4 c = -10

And we will find the discriminant: $b^{2} -4ac = 4^{2} -4(-3)(-10) = 16-120=-104$

Therefore our discriminant is less than zero and we know that our equation will have two solutions in the complex numbers.

To proceed to solve the equation we will use the general formula

x₁= (-b+√b²-4ac)/2a

so x₁ = $\frac{-4+\sqrt{-104} }{2(-3)} \\\frac{-4+\sqrt{-104} }{-6}\\\frac{-4+2\sqrt{-26} }{-6} \\\frac{-4+2i\sqrt{26} }{-6} \\\frac{2}{3} -\frac{1}{3} i\sqrt{26}$

The second solution x₂ = (-b-√b²-4ac)/2a

so x₂= $\frac{-4-\sqrt{-104} }{2(-3)} \\\frac{-4-\sqrt{-104} }{-6}\\\frac{-4-2\sqrt{-26} }{-6} \\\frac{-4-2i\sqrt{26} }{-6} \\\frac{2}{3} +\frac{1}{3} i\sqrt{26}$

These are our two solutions in the imaginary numbers.

7 0

3 years ago

Raj weighs a book and rounds the weights to the nearest tenth. Does this weight round to 1.5 pounds?

Lelu [443]

Answer:

True

Step-by-step explanation:

1.45 the 5 is equal/above it so it is true

7 0

2 years ago

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