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3 years ago

What is the answer for -4 (12)= what is the answer

Mathematics

2 answers:

Naddik [55]3 years ago

8 0

Answer:

-48

Step-by-step explanation:

12 x 4= 48 just add negative sign to 48.

Hope this helps :3

bulgar [2K]3 years ago

6 0

Answer:

-4(12) = -48

Step-by-step explanation:

Negative stay negative and 4 multiply by 12 is 48 from the multiplication table, therefore -4 multiply by 12 is -48.

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2) two florist purchased flower bouquets and vases at the same store. The first florist bought 2 flower bouquets and two vases f

Feliz [49]

Let
b---------> the cost of one flower bouquet
v--------> the cost of one vase.

we know that
2b+2v=12.50-----> Multiplied by -1------------->-2b-2v=-12.50
8b+2v=29---------------------------------------------> 8b+2v=29
I add the two equations ------------------------
6b=16.50
b=2.75
2*2.75+2*v=12.50---------------> v=(12.50-5.5)/2---------> v=3.5

the answer is
the cost of one flower bouquet is $2.75
the cost of one vase is $3.5

7 0

3 years ago

Adding and Subtracting Functions F(x)=x^2+4 G(x)=x-1 Find (g+f)(x)

Lady_Fox [76]

Answer:

Step-by-step explanation:

$(g+f)(x)=g(x)+f(x)=x-1+x^2 +4=x^2 +x+3$ $x^2 +x+3$

4 0

2 years ago

A simplified model for the movement of the price of a stock supposes that on each day the stock’s price either moves up 1 unit w

DanielleElmas [232]

Answer:

(a) The probability that after 2 days the stock will be at its original price is

$P_a=2p(1-p)$

(b) The probability that after 3 days the stock’s price will have increased by 1 unit is

$P_b=3p^2(1-p)$

(c) Given that after 3 days the stock’s price has increased by 1 unit, the probability that it went up on the first day is

$P=2/3$

Step-by-step explanation:

(a) What is the probability that after 2 days the stock will be at its original price?

For the price of the stock to be in its original price, there are two ways it can happen:

1) the price increases the first day by one unit and decreases by one unit the second day. The probability of this event is P=p*(1-p).

2) the price decreases the first day by one unit and increases by one unit the second day. The probability of this event is P=(1-p)p.

The probability that after 2 days the stock will be at its original price is the sum of the probability of this two events:

$P=P_1+P_2=p(1-p)+(1-p)p=2p(1-p)$

(b) What is the probability that after 3 days the stock’s price will have increased by 1 unit?

For this event to happen (one unit increase in 3 days), it must have happened 2 increases in price and 1 decrease.

There are 3 possible ways of this to happen:

1) decrease in the first day.

2) decrease in the second day.

3) decrease in the third day.

Each one ot this 3 events has the same probability $P_i=p^2(1-p)$ .

So the probability that after 3 days the stock’s price will have increased by 1 unit is equal to the sum of the probabilities of this events:

$P=P_1+P_2+P_3=3p^2(1-p)$

(c) Given that after 3 days the stock’s price has increased by 1 unit, what is the probability that it went up on the first day?

According to the answer (c), there are 3 events where the price has increase by one unit after 3 days, each one with equal probability $P_i=p^2(1-p)$ .

Of these 3 events, there are 2 that have an increase in the first day. So we can conclude that, if the events have the same probability, the probability of the increase in the first day, given that the price has increased by one unit in 3 days, is P=2/3.

8 0

4 years ago

Help please asap!!! working too please not just the answers!!

omeli [17]

Answer:

Area = 4600m

explanation: I worked it out in the image attached if that helps let me know if you need a more in depth explanation step by step