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Paha777 [63]
3 years ago
10

A 22inch piece of steel is cut into three pieces so that the second piece is twice as long as the first piece, and the third pie

ce is one inch more than four times the length of the first piece. Find the length of the pieces
Mathematics
1 answer:
Dovator [93]3 years ago
8 0

Answer:

<h2>The length of the pieces is 3 inch, 6 inch and 13 inch.</h2>

Step-by-step explanation:

Let, the length of the first piece is x inch.

Hence, the length of the second piece is 2x.

It is given that, the length of the third piece is one inch more than four times of the first piece. Hence, the length of the third piece is 4x + 1 inch.

The total length of the steel is 22 inch.

Hence, x + 2x + 4x + 1 = 22

or, 7x = 21

or, x = 3.

The length of the second piece is 2x = 2\times3 = 6 inch.

The length of the third piece is 4x + 1 = 12 + 1 = 13 inch.

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In triangle ABC, b = 600, ∠B = 11°, and ∠C = 75°. Find a.​
vodomira [7]

Answer:

Step-by-step explanation:

We could use the Law of Sines if we only knew what angle A was. It just so happens that by the Triangle Angle-Sum Theorem, angle A is equal to

180 - B - C. Therefore,

angle A = 180 - 11 - 75 so

angle A = 94. And the Law of Sines is

\frac{sin94}{a}=\frac{sin11}{600} and cross multiply to get

600sin94 = asin11 and solve for a:

a=\frac{600sin94}{sin11} gives you that

a = 3136.85

8 0
3 years ago
I need help asap it is due in an hour plz help I've been trying to answer for hours. #6
klemol [59]

Answer:

116.7 years

Step-by-step explanation:

Graph the two equations to find the point they intersect, that is then the answer.

3 0
3 years ago
PLEASE HELP Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM.
worty [1.4K]

We have to find the perimeter of the triangle KLM.

We have been given that the length of the side LM=12, m\angleK=60^\circ, and m\angle M= 45^\circ

Refer the attached image.

In a triangle sum of three angles should be 180^\circ.

So,

m\angle K+m\angle L+m\angle M=180^\circ

Plugging the values of angle K and angle M, we get:

60^\circ+m\angle L+45^\circ=180^\circ

So,

m\angle L=180^\circ-105^\circ=75^\circ

Now, that we have the measure of angle L, we will apply sine rule to find the length of the sides KL and KM.

Using the sine law for the triangle KLM, we get:

\frac{sin K}{LM}=\frac{sin L}{KM}=\frac{sin M}{KL}

Refer the image. Plugging the value of the sides of the triangle KLM and the angles of the triangle KLM, we get:

\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}=\frac{sin 45^\circ}{x}

Now using,

\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}

We get the value of 'y'

y=\frac{sin 75^\circ}{sin 60^\circ} \times 12=\frac{0.9659}{0.866} \times 12=13.38

So the length of the side KM is 13.38 units.

Now using,

\frac {sin 60^\circ}{12}=\frac{sin 45^\circ}{x}

We get the value of 'x'

x=\frac{sin 45^\circ}{sin 60^\circ} \times 12=\frac{0.707}{0.866} \times 12=9.79

So the length of the side KL is 9.79 units.

Now, to find the perimeter of the triangle KLM we need to sum up the length of the sides of the triangle KLM.

The perimeter of the triangle KLM = KL+ LM + KM = 9.79 + 12 + 13.38 = 35.17 units

6 0
3 years ago
Read 2 more answers
Select the answer that describes the properties of a square.
sveta [45]

Answer:

Two pairs of parallel sides

All sides congruent

Four right angles

5 0
3 years ago
The Hiking Club plans to go camping in a State park where the probability of rain on any given day is 69%. What is the probabili
Lynna [10]

Answer:

0.013

Step-by-step explanation:

Use binomial probability:

P = nCr pʳ (1−p)ⁿ⁻ʳ

where n is the number of trials,

r is the number of successes,

and p is the probability of success.

Given n = 6, p = 0.69, and r = 0 or 1:

P = ₆C₀ (0.69)⁰ (1−0.69)⁶⁻⁰ + ₆C₁ (0.69)¹ (1−0.69)⁶⁻¹

P = (1) (1) (0.31)⁶ + (6) (0.69) (0.31)⁵

P = 0.013

4 0
3 years ago
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