Answer:
C,D,,B) The molecule is likely a sugar.
Explanation:
The molecule is(hexose) a glucose.It is a sugar formed as the products of photosynthesis.It is also a carbohydrate because all sugars are CHO,although not all CHO are sugars.It is the smallest components of cell membranes.Protein are the largest components based on molecular mass,while phospholipids are the largest components.
The three major elements in the molecule are Carbon.Hydrogen and Oxygen. The general formula of carbohydrate is Cx(H2O)y. The ratio of hydrogen to oxygen is 2:1.Thus the hydrate refers to the water content.
Sugar as monosaccharide glucose is the simplest form with general molecular formula of (CH2O)n where may be n = 3 to 6. In glucose n=6,and it is called Hexose. Therefore the molecule of glucose is C6H1206 in ratio 1:2:1.
The arrangement of glucose could be in straight chain or ring structure,Hexose sugar of glucose and pentose can be ring structure.They have C-H chain length long enough to form ring structure.
In glucose this can either be alpha or beta ring structure. Therefore the molecule is either the alpha or beta-glucose ring.
Answer: False
Explanation: as the muscles shortens due to contraction, the actin filaments from opposite ends of the sarcomere approach each other. So the two Z bands come closer with reduction in length of the sarcomere
<span>DNA the nitrgenous bases guanine and adenine are
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Because the moon is very close to the earth. If the sun was between the moon and the earth the earth would burn up
Answer:
Explained
Explanation:
Due to lack of of Triose phosphate isomerase cell will be unable to interconvert Dihydroxyacetone to glyceraldehyde 3 phosphate.
And the cells will be able to complete the glycolysis only in the presence of glyceraldehyde 3 phosphate which will generate 2 ATP and hence the net ATP gain during whole process in anaerobic condition will be Zero. This will lead to the dath of the mutant yeast.
a) While in case of aerobic condition, only one molecule of pyruvate will also be able to produce more ATP compared to anaerobic condition by further oxidation which is sufficient for yeast to survive.
b) the cells will be able to complete the glycolysis only in the presence of glyceraldehyde 3 phosphate which will generate 2 ATP and hence the net ATP gain during whole process in anaerobic condition will be Zero. This will lead to the death of the mutant yeast.