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OLEGan [10]
3 years ago
10

You start driving north for 11 miles, turn right, and drive east for another 60 miles.

Mathematics
1 answer:
Elis [28]3 years ago
4 0

Answer:

61 miles.

Step-by-step explanation:

Given: driving north for 11 miles and drive east for another 60 miles.

As given in the question, the travelling pattern show a right angle triangle, where hypotenuse line is the way to return back directly to starting point. As shown in picture attached.

∴ we can say, adjacent (a) is 11 miles and opposite (b) is 60 miles

Now, using Pythagoras theorem to get distance to return.

h^{2} = a^{2} +b^{2}

⇒ h^{2} = 11^{2} +60^{2}

⇒ h^{2} = 121+3600= 3721

⇒ h= \sqrt{3721}

∴h= 61

∴ 61 miles need to be travel to return back directly to starting point.

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Trigonometry . What
Kryger [21]

Answer:

Ques 11: 123.08 meters.

Ques 12: 269.4 meters.

Ques 13: 211.27 meters.

Step-by-step explanation:

Ques 11: We have that the angle of elevation from the ship to the top of the lighthouse is 18° and the height of the lighthouse is 40 m.

It is required to find the distance of the ship from the shore, say 'x' m.

As, we have, \tan \theta=\frac{opposite}{adjacent}

⇒ \tan 18=\frac{40}{x}

⇒ x=\frac{40}{\tan 18}

⇒ x=\frac{40}{0.325}

⇒ x = 123.08 m.

Thus, the distance of the ship from the shore is 123.08 meters.

Ques 12: We have, length of the kite is 300 m and the angle made by the string is 64°.

It is required to find the height of the kite, say 'x' m.

As, we have, \sin\theta=\frac{opposite}{hypotenuse}

⇒ \sin 64=\frac{x}{300}

⇒ x=300\times \sin 64

⇒ x=300\times 0.898

⇒ x = 269.4 m.

Hence, the height of the kite is 269.4 meters.

Ques 13: We have, the wreckage is found at the angle of 12° and the diver is lowered down by 45 meters.

It is required to find the distance covered by the diver to reach the wreckage, say 'x' m.

As, we have, \tan \theta=\frac{opposite}{adjacent}

⇒ \tan 12=\frac{45}{x}

⇒ x=\frac{45}{\tan 12}

⇒ x=\frac{45}{0.213}

⇒ x = 211.27 m.

Thus, the distance covered by the diver to reach the wreckage is 211.27 meters.

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