Question

What is the vertex of the graph of the function f(x)=x^2+8x-2 !?

Answer 1

Answer:

(-4, -18).

Step-by-step explanation:

f(x = x^2 + 8x - 2         Completing the square on x^2 + 8x:-

     = (x + 4)^2 - 16 - 2

     = (x + 4)^2 - 18

- which is the vertex form of f(x)

The vertex of

(x - h)^2 + k  is at (h, k)

So the vertex of f(x) is at (-4, -18)