The expected count of visits is the mean or average visits to each feeder
The expected count of visits to the third feeder is 87.5
<h3>How to determine the expected count of visit?</h3>
The table of values is given as:
Feeder 1 2 3 4
Observed visits 80 90 92 88
In this case, the null hypothesis implies that the visits to each feeder are uniformly distributed
So, the expected count is calculated using:
Expected count =Visits/Feeders
This gives
Expected count = 350/4
Evaluate the quotient
Expected count = 87.50
Hence, the expected count of visits to the third feeder is 87.5
Read more about chi square goodness of fit test at:
brainly.com/question/4543358
Answer:
![\frac{dy}{dx}=-[(\frac{5x+24}{36x-6x^2})]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D-%5B%28%5Cfrac%7B5x%2B24%7D%7B36x-6x%5E2%7D%29%5D)
Step-by-step explanation:
Given function:
y =
we know
= ln(A) - ln(B)
thus,
y = 
or
also,
ln(Aⁿ) = n × ln(A)
thus,
y = 
therefore,
![\frac{dy}{dx}=[(\frac{3}{2})\times\frac{1}{(6-x)}\times(0 - 1)] - [ (\frac{2}{3})\times\frac{1}{x}\times1]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D%5B%28%5Cfrac%7B3%7D%7B2%7D%29%5Ctimes%5Cfrac%7B1%7D%7B%286-x%29%7D%5Ctimes%280%20-%201%29%5D%20-%20%5B%20%28%5Cfrac%7B2%7D%7B3%7D%29%5Ctimes%5Cfrac%7B1%7D%7Bx%7D%5Ctimes1%5D)
or
or
![\frac{dy}{dx}=-[(\frac{3(3x)+2\times2(6-x)}{2(6-x)\times(3x)})]](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%3D-%5B%28%5Cfrac%7B3%283x%29%2B2%5Ctimes2%286-x%29%7D%7B2%286-x%29%5Ctimes%283x%29%7D%29%5D)
or
How do you do a box and whisker plot using 18,18,17,19,20,22,22,22,22,23,25 and26
sashaice [31]
What a whisker plot exactly
To find the area you do base times height. Base is the number across,and height is the number that is up and down.So in this case you will multiply 9 and 5 and 9 and 7 and get 45 and 72.Then you will add 45 and 72 together and get 117. So the area is 117. Answer 117. Hope this helps :D.
