Question

How do you solve for a side in a right triangle that has a hypotenuse of 10, an angle of 35, and the side across from the angle is x?

Answer 1

$\sin \theta = \dfrac{\textrm{opposite}}{\textrm{hypotenuse}}$

$\sin 35^\circ = \dfrac{x}{10}$

$x = 10 \sin 35^\circ$

That's the exact answer; they usually want a calculator approximation at this point,

$x \approx 5.735$