Bet add me tho bc adding u alot of wrk ftojayyyy
(2x^2+6x-11)-(5x^2-x+7)
Pretend that there is a -1 in front of the second bracket
-1(5x^2-x+7)=-5x^2+x-7
2x^2+6x-11-5x^2+x-7
2x^2-5x^2+6x+x-11-7 ( combine like terms)\
-3x^2+7x-18
Answer: d. -3x^2+7x-18
Answer:
Don't take my word for it because I havent dont this in a while but I believe it is the top right
A square has equal side lengths, so using the pyth. theorem...
let x = side length
2x² = 24²
2x² = 576
x² = 288
x = 17 approx. because √289 = 17
answer: 17 m
No, just keep factoring until you cannot factor any further.
example:
90
.^
9*10
^....^
3*3*2*5
I could also start with 15*6, 3*30 or whatever. but the final answer will still be
2*3*3*5 = 2*3^2*5.