$x-2y=5 \\
3x-5y=8 \\ \\
\hbox{solve the first equation for x:} \\
x-2y=5 \ \ \ |+2y \\
x=2y+5 \\ \\
\hbox{substitute 2y+5 for x in the second equation:} \\
3(2y+5)-5y=8 \\
6y+15-5y=8 \\
y+15=8 \ \ \ |-15 \\
y=-7 \\ \\
x=2y+5=2 \times (-7)+5=-14+5=-9 \\ \\
\boxed{(x,y)=(-9,-7)}$

6 0

3 years ago

Which is the graph of y= square root x - 5 - 1

professor190 [17]

Answer:

Graph D

Step-by-step explanation:

3 0

3 years ago

The figure is made up of a square and a rectangle. Find the area of the shaded region.

inn [45]

Answer:

$10 \: { \: m}^{2}$

Step-by-step explanation:

area of the shaded region = Area of triangle formed in rectangle with base (10 - 6 = 4) 4m and height 2 m + Area of triangle formed in square with base 2 m and height 6 m

$= \frac{1}{2} \times 4 \times 2 +\frac{1}{2} \times 2\times 6 \\ \\ = 4+6 \\ \\ = 10 \: { \: m}^{2}$

8 0

3 years ago

Read 2 more answers