Find the surface area of the rectangular prism (above) using its net (below).

The report "The New Food Fights: U.S. Public Divides Over Food Science" states that younger adults are more likely to see foods

zheka24 [161]

Solution :

$n_1=178, \hat p_1 = 0.48$

$n_2=427, \hat p_2 = 0.38$

$\hat p_1=\frac{x_1}{n_1}$

$x_1=n_1 \hat p_1$

= 178 x 0.48

= 85.44

≈ 85

$x_2=n_2 \hat p_2$

= 427 x 0.38

= 162.26

≈ 162

a). Yes, the sample sizes are large enough to use the large sample confidence interval so as to estimate the difference in the population proportions.

Let $\hat p_1 = 0.48, \ \ \hat p_2 = 0.38, n_1 = 178 \ \ n_2 = 427$

Where the $\text{subscript indicates}$ the age $18-29$ group and the 2 - subscript indicates the age $50-64$ group.

Since $n_1 \hat p_1 = 85.44$

$n_1(1- \hat p_1)=92.56, \ \ n_2\hat p_2 = 162.26, \ n_2(1-\hat p_2) = 264.74$

are all at least 10, the sample sizes are large enough to use the large sample confidence interval.

$P_0=\frac{x_1+x_2}{n_1+n_2}$

$=\frac{85.44+162.26}{178+427}$

= 0.409421

$P_0 = 0.4074$

$Q_0=1-P_0$

= 1 - 0.4094

= 0.5906

b). 90% confidence interval is

$=\left( \hat p_1- \hat p_2 \pm \frac{z \alpha}{2} \times \sqrt{P_0Q_0\left(\frac{1}{n_1}+\frac{1}{n_2}}\right) \right)$

$=\left( 0.48-0.38 \pm \frac{z \times 0.10}{2} \times \sqrt{0.4094 \times 0.5906\left(\frac{1}{178}+\frac{1}{427}}\right) \right)$

$=(0.1 \pm z 0.05 \times 0.04387082)$

$=(0.1 \pm 1.64 \times 0.0439)$

$=(0.1 - 0.071996, 0.1+0.071996)$

$=(0.028004, 0.171996)$

$=(0.0280, 0.1720)$

c). Zero is not included in the confidence interval. Answer is no. The difference in the two population proportion are different from each other.

5 0

3 years ago

A 16-fl oz bottle of juice costs $2.00 what is the unit cost

krok68 [10]

Hello!

I believe all you have to do is divide 16 by 2.00.

The answer is 8 opd or ounce per dollar.

Hope this helps! ☺♥

8 0

4 years ago

When looking at the rational function f of x equals the quantity x minus one times the quantity x plus two times the quantity x

Luba_88 [7]

As per the given question, the expression of the function $f(x)$ is as:

$f(x)=\frac{(x-1)(x+2)(x+4)}{(x+1)(x-2)(x-4)}$

Now, as per the definition of zeros, the zero is that value of x which when plugged into the function should make the function zero (it is also called "making the function vanish"). <u>In our case, plugging in "zero values" of x should make the numerator zero without making the denominator zero.</u> Now, if we plug in the given values of x, which are x=-1, x=2 and x=4 in the function we see that the <u>numerator does not become a zero but the denominator does</u>.

Thus, x=-1, x=2 and x=4 are not the zeros of the function and therefore, Sue is wrong. However, we do have discontinuities at the aforementioned values of x because the denominator becomes a zero at those points and as per the definition of a discontinuity the denominator should be a zero at that point. Therefore, Ed is correct.

8 0

4 years ago

Sarika’s house is 5 km from her office. She covered 4 ½ by train and the remaining by walk.

givi [52]

Answer:

1/2 km or 0.5 km

Step-by-step explanation:

In the attached file