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alexgriva [62]
2 years ago
10

Given that g(x)=-X+2, find f(4)

Mathematics
1 answer:
vredina [299]2 years ago
4 0

Answer:

See below.

Step-by-step explanation:

g(x) and f(4) refer to different functions.

Since we are not given f(x) is, we cannot answer the question.

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It is now twenty-seven minutes past six. What time will it be in 3 hours and 25 minutes?
stealth61 [152]

Answer:

9:52

Step-by-step explanation:

First, let's rewrite "twenty-seven minutes past six", into a standard digital clock form. We could write 6:27. Now, it's easier to see that if we add 3 hours first, we would get to 9:27. And then if we add 25 minutes, we will get to 9:52.

5 0
3 years ago
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Dara buys a small drink for $1.75. A large drink costs 1.6 times as much as a small drink. How much does a large drink cost?
77julia77 [94]
I believe its $6.95 but i did that in my head so i might be wrong
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3 years ago
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A dataset lists full IQ scores for a random sample of subjects with low lead levels in their blood (sample 1) and another random
Alenkasestr [34]

Answer:

a. Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

b. t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

c. p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

Step-by-step explanation:

a. State and label the null and alternative hypotheses.

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 >\mu_2

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 \leq 0

Alternative hypothesis: \mu_1 -\mu_2>0

Our notation on this case :

n_1 =78 represent the sample size for group 1

n_2 =21 represent the sample size for group 2

\bar X_1 =92.88 represent the sample mean for the group 1

\bar X_2 =86.90 represent the sample mean for the group 2

s_1=15.34 represent the sample standard deviation for group 1

s_2=8.99 represent the sample standard deviation for group 2

b. State the value of the test statistic.

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{s^2_2}{n_2}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom. If we replace the values given we have:

t=\frac{(92.88 -86.90)-(0)}{\sqrt{\frac{15.34^2}{78}}+\frac{8.99^2}{21}}=2.282

Now we can calculate the degrees of freedom given by:

df=78+21-2=97

c. Find either the critical value(s) and draw a picture of the critical region(s) or find the P-value for this test. Indicate which method you are using: ( CIRCLE ONE: Critical value / P-value )

Method used: P value

And now we can calculate the p value using the altenative hypothesis, since it's a right tail test the p value is given by:

p_v =P(t_{97}>2.287) =0.0122

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (Low Blood Lead level) is significantly higher than the mean for the group 2 (High Blood Lead level).  

6 0
3 years ago
(3,-4, slope = undefined
Anni [7]



lines with undefined slope are vertical

equation are  in form of x constant

through the points ( 3 , -4)

the line is x=3


4 0
3 years ago
What does y=-1/2x-4
Anvisha [2.4K]

Answer:

y = -1/2x - 4

From this, you can tell it's in slope-intercept form, has a slope of -1/2, and a y-intercept of -4.

I've included a picture of what this equation looks like.

5 0
2 years ago
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