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3 years ago

Jack's goal is to lose 4.25 pounds every month. If he keeps this up, how much weight will he have lost after 9.5 month

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

6 0

Answer:

40.38 pounds

Step-by-step explanation:

9.5 x 4.25 = total weight lost

9.5 x 4.25 = 40.375 = 40.38 pounds

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How to divide 0.62 divide 0.01

NARA [144]

Move the decimal to the left two places

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4 years ago

Rewrite the following equation in log form: 2^2 = 4

Finger [1]

We have to write

$2^2 =4$

In log form

To convert exponential equation to log equation, we have to use the following rule $If \ a^b = c, \ then \ b=log_{a} c$

So we will get

$If \ 2^2 =4, \ then \ 2 = log_{2} 4$

$log_{2}4=2$

And that's the required log form .

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4 years ago

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How would one solve this

yaroslaw [1]

Sorry i really need points

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3 years ago

Candice spent 5 1/4 hours doing her homework. Her brother, Ronald, spent 1/2 that number of hours doing his homework. How many h

Elden [556K]

Let

x-----> the number of hours that Candice spent doing her homework

y-----> the number of hours that Ronald spent doing his homework

we know that

$x=5\frac{1}{4}\ hours$

convert mixed number to an improper fraction

$5\frac{1}{4}\ hours=\frac{5*4+1}{4}= \frac{21}{4}\ hours$

$x=\frac{21}{4}\ hours$ -------> equation A

$y=\frac{1}{2}x$ ------> equation B

Substitute equation A in equation B

$y=\frac{1}{2}*\frac{21}{4}=\frac{21}{8}\ hours$

convert an improper fraction to a mixed number

$\frac{21}{8}\ hours=2.625=2+0.625=2+\frac{5}{8}=2\frac{5}{8}\ hours$

therefore

<u>the answer is the option B</u>

$2\frac{5}{8}\ hours$

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3 years ago

Read 2 more answers

Area triangles? it says show work so pls do

coldgirl [10]

$\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}$

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times h) \\ \\ \leadsto \frac{1}{2} \times 30h \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{30}h \\ \\ \leadsto1 \times 15h \\ \\ \leadsto \: h = 15 \: yd$

Therefore, the require height is 15 yd.

$\green\star$ Proof:

$\frac{1}{2} \times (b \times h) \\ \\ \leadsto \frac{1}{2} \times (30 \times 15) \\ \\ \leadsto \frac{1}{ \cancel{2}} \times \cancel{450} \\ \\ \leadsto1 \times 225 \\ \\ area = 225 {yd}^{2}$

$\boxed{ \frak \red{brainlysamurai}}$

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2 years ago