What is the value of the expression [(1+5)x2-5]x2
2 answers:
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9514 1404 393
Answer:
(x, y) = (-6, 15) and (2, -1)
Step-by-step explanation:
You can start by subtracting the second equation from the first.
(y) -(y) = (x^2 +2x -9) -(-2x +3)
0 = x^2 +4x -12 . . . . . . collect terms
0 = (x +6)(x -2) . . . . . . . factor
Solutions for x are -6 and +2. These values make the factors zero.
The corresponding solutions for y are ...
y = -2(-6) +3 = 15
y = -2(2) +3 = -1
Solutions to the system of equations are ...
(x, y) = (-6, 15) and (2, -1)
** 3x - x -7 = 3
2x = 10
x = 5
** <span>6. 3x - 3 -x = 3
18x - 3 - x = 3
17x = 6
x = </span>
** <span>7. -1 - 2x + 3x = 5
-7 - 2x + 3x = 5
-7 + x = 5
x = 12
** </span><span>8. 3x - 22 - x = 6
24x - 22 - x = 6
23x = 28
x = </span>
** <span>9. 2x + 3x -10 = 10
18x + 3x - 10 = 10
21x = 20
x = </span>
2x = 10
x = 5
** <span>6. 3x - 3 -x = 3
18x - 3 - x = 3
17x = 6
x = </span>
** <span>7. -1 - 2x + 3x = 5
-7 - 2x + 3x = 5
-7 + x = 5
x = 12
** </span><span>8. 3x - 22 - x = 6
24x - 22 - x = 6
23x = 28
x = </span>
** <span>9. 2x + 3x -10 = 10
18x + 3x - 10 = 10
21x = 20
x = </span>