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Black_prince [1.1K]
4 years ago
10

The graph shows two lines, A and B.

Mathematics
2 answers:
Greeley [361]4 years ago
5 0

Answer: a) Only one solution.

b) (4,4)

Step-by-step explanation:

Since we have given that

Two lines A and B .

Part A: How many solutions does the pair of equations for lines A and B have?

We can see that at some point the line A is intersected by line B.

That means it has only one solution as it becomes intersecting lines.

That type of lines has unique solution i.e one solution only.

Part B: What is the solution to the equations of lines A and B?

As we can see from the graph that the lines have cut themselves at (4,4).

That means At 4 units of x -coordinate and at 4 units of y-coordinate as well.

miss Akunina [59]4 years ago
3 0
Part A: As we have learned when given a pair of equations, we must always find a Point of Intersection....or, in other words...the solution of the lines given to us. As we know there can be one solution, in this case we view the graph; see where they intersect, and realize that the solution to these lines (Point of Intersection) is at (4,4).

Thus, your answer.
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Perform the indicated operations; reduce the answer to lowest terms. a. 3⁄10 + 6⁄10 b. 1⁄3 + 1⁄4 + 1⁄6 c. 5⁄6 – 3⁄6 d. 2⁄3 – 6⁄1
Setler [38]

Answer:

a. 3⁄10 + 6⁄10 = 9/10

b. 1⁄3 + 1⁄4 + 1⁄6 = 3/4

c. 5⁄6 – 3⁄6 = 1/3

d. 2⁄3 – 6⁄10 = 1/15

e. 4⁄10 × 3⁄7 = 6/35

f. 1⁄6 × 6⁄15 = 1/15

g. 1⁄8 ÷ 4⁄9 = 9/32

h. 1⁄5 ÷ 3⁄4 = 4/15

Step-by-step explanation:

a. 3⁄10 + 6⁄10

= 3*1 + 6*1 / 10

= 3+6/10

= 9/10

b. 1⁄3 + 1⁄4 + 1⁄6

since denominators are different we take LCM of 3,4,6 which is 12

= 1*4 + 1*3 + 1*2 / 12

= 4+3+2/12

= 9 ÷ 3 / 12 ÷ 3

= 3 / 4

c. 5⁄6 – 3⁄6

= 5 - 3 / 6

= 2 ÷ 2 / 6 ÷ 2 = 1/3

d. 2⁄3 – 6⁄10

LCM of 3 and 10 is 30

= 2 * 10 - 6 * 3 / 30

= 20 - 18 / 30

= 2 ÷ 2 / 30 ÷ 2 = 1/15

e. 4⁄10 × 3⁄7

= 12 ÷ 2 / 70 ÷ 2 = 6/35

f. 1⁄6 × 6⁄15

= 6 ÷ 6/90 ÷ 6 = 1/15

g. 1⁄8 ÷ 4⁄9

= 1/ 8 * 9/4

=9/32

h. 1⁄5 ÷ 3⁄4

=1/5 * 4/3

= 4/15

3 0
3 years ago
Read 2 more answers
Rewrite in simplest terms: (-x+8y)+(-10x-6y)(−x+8y)+(−10x−6y)
Nina [5.8K]

Answer:

10x² - 48y² - 11x + 2y - 74xy

Step-by-step explanation:

(-x+8y)+(-10x-6y)(−x+8y)+(−10x−6y)

Rearranging,

=> - x - 10 x + 8y - 6y + (-10x-6y)(−x+8y)

=> - 11x + 2y + 10x² - 48y² + 6xy - 80xy

=> 10x² - 48y² - 11x + 2y - 74xy

7 0
3 years ago
Assume that the red blood cell counts of women are normally distributed with a mean of 4.577 million cells per microliter and a
serg [7]

Answer:

82.31% of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per​ microliter

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 4.577, \sigma = 0.382

Approximately what percentage of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per​ microliter?

This is the pvalue of Z when X = 5.4 subtracted by the pvalue of Z when X = 4.2. So

X = 5.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.4 - 4.577}{0.382}

Z = 2.15

Z = 2.15 has a pvalue of 0.9842

X = 4.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{4.2 - 4.577}{0.382}

Z = -0.99

Z = -0.99 has a pvalue of 0.1611

0.9842 - 0.1611 = 0.8231

82.31%  of women have red blood cell counts in the normal range from 4.2 to 5.4 million cells per​ microliter

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