All categories

3 years ago

Pick any Martin Luther king speech 2-4 minutes and pick a inspirational reason why you picked that speech!!!!!!!!!! Thanks

Mathematics

1 answer:

Zigmanuir [339]3 years ago

3 0

Answer:

I Have A Dream

The reason I had picked this speech is because it is the most known and most inspirational speech he had ever made. This speech inspired people all around the world to be aware of the problems we have in society and to start making a change because if you don't make a change who will? That speech brought attention to what was and still is a problem in America and he showed that he wants to see a change so does everyone else. After Martin Luther King had presented that speech to all those people congress started to move faster to pass the Civil Rights Act.

A good way to think about how inspirational that speech he had made was is to think about how many things would be different today if he had not made that speech. If you think about it we have a whole entire holiday dedicated to Martin Luter King and that speech was probably one of those things that he had done to earn such a holiday. In conclusion, Martin Luther King's speech brought so much attention that inspired so many people, especially African Americans, that so much attention was brought to those problems stated that the congress couldn't go any longer with the injustices going on and were forced to make a change.

You might be interested in

If an aircraft is present in a certain area, a radar correctly registers its presence with probability 0.99. if it is not presen

pishuonlain [190]

Answer:

A) 0.005

B) 0.001

C)0.0495

Step-by-step explanation:

Let A be the event that an aircraft is present and let B be the event the radar registers its presence.. Thus;

P(A) = Probability that an aircraft is present

P(A') = Probability that an aircraft is not present

P(B) = Probability that the radar generates an alarm

P(B') = Probability that the radar doesn't generate an alarm

Thus from what we are given, we have;

P(A) = 0.05

P(A') = 0.95

P(B) = 0.99

P(B') = 0.01

P(B|A') = 0.1

A) Probability of a false alarm will be;

P(A' ∩ B) = P(A) × P(B|A')

P(A' ∩ B) = 0.05 × 0.1 = 0.005

B) probability of missed detection is;

0.1 × (1 - 0.99) = 0.001

C) probability that an aircraft is present given that the radar registers a presence will be;

P(A ∩ B) = P(A) × P(B)

P(A ∩ B) = 0.05 × 0.99

P(A ∩ B) = 0.0495

5 0

3 years ago

A man travels 20 km by car from Town P to Town Q at an average speed of x km/h. He finds that the time of the journey would be s

yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

$x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2} = \frac{1 \pm 9 }{-0.4}$

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0

3 years ago

On Tuesday, 14 students handed in a permission slip for a field trip. On Thursday, twice as many students handed in their permis

VLD [36.1K]

14+(2x14)+7 is the correct answer.

7 0

3 years ago

A merchant has120 litres and 180 litres of two kinds of oil. He wants to sell the oil by filling the two kinds in tins of equal

fredd [130]

Answer:

60 litres

Step-by-step explanation:

To obtain the greatest volume of the tin, we calculate the highest common factor of both 120 and 80

Factors of :

80 : 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

120 : 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

The highest common factor is 60.

Hence, the greatest volume of the tin would be 60 litres

4 0

3 years ago

The population of a town was 230000. For 12 years, the population grew by 4% per year, compounded continuously. What was the pop

kap26 [50]

Answer: 371697

Step-by-step explanation:

For continuously compounded values, we use the formula Pe^rt, or Pert. P is our principal/initial value, 230000. e is the constant e, r is our rate, 4% or .04, t is our time, 12. So, 230000*e^(.04*12)=371697.112504, rounding down, 371697.

8 0

3 years ago