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3 years ago

Help, please this is my last question and i cant figure it out

Mathematics

1 answer:

allsm [11]3 years ago

4 0

Hi! Your answer is y = x + 4

Please see an explanation for a better and clear understanding to your problem!

Any questions about my answer and explanation can be asked through comments! :)

Step-by-step explanation:

Here are the reasons why it's A choice which is y = x + 4.

The graph passes through y-axis at (0,4) which makes it obvious that the graph has y-intercept/b-value equal 4.
The graph has slope of 1. We can tell by rise over run (A glance can tell that the graph has slope of 1.)
Other choices have y-intercept at (0,0) also known as "origin point". The graph shown doesn't pass an origin point but passes through (0,4) as explained.

Here is the slope-intercept form, it might benefit you in some questions!

$\HUGE{y=mx+b}$

where m = slope and b = y-intercept.

Hope this helps! :)

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10 points<br> Multiply (3.5x10^-6)x(2x10^-4) *

Molodets [167]

Answer:

Step-by-step explanation:

Multiply 3.5 and 2 together, obtaining 7.

Then add the exponents -6 and -4, obtaining -10.

The product is thus 7·10^(-10), or, after simplification,

7·10^(-9), or

----------

10^9

8 0

3 years ago

I don't understand how you do it

Alekssandra [29.7K]

Container A:
y=-6x+800
800 is y intercept( it already have 800 before leaking)
leaking means that its went down so it had to be negative -6x)
container B:
y=-10x+1000
same thing with a container B
-6x+800=-10x+1000 = 800-6x=1000-10x

6 0

3 years ago

Need help really bad

natali 33 [55]

The answer will be 6.

5 0

3 years ago

An equilateral triangle is inscribed in a circle of radius 6r. Express the area A within the circle but outside the triangle as

Paul [167]

Answer:

$A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}$

Step-by-step explanation:

We have been given that an equilateral triangle is inscribed in a circle of radius 6r. We are asked to express the area A within the circle but outside the triangle as a function of the length 5x of the side of the triangle.

We know that the relation between radius (R) of circumscribing circle to the side (a) of inscribed equilateral triangle is $\frac{a}{\sqrt{3}}=R$ .

Upon substituting our given values, we will get:

$\frac{5x}{\sqrt{3}}=6r$

Let us solve for r.

$r=\frac{5x}{6\sqrt{3}}$

$\text{Area of circle}=\pi(6r)^2=\pi(6\cdot \frac{5x}{6\sqrt{3}})^2=\pi(\frac{5x}{\sqrt{3}})^2=\frac{25\pi x^2}{3}$

We know that area of an equilateral triangle is equal to $\frac{\sqrt{3}}{4}s^2$ , where s represents side length of triangle.

$\text{Area of equilateral triangle}=\frac{\sqrt{3}}{4}s^2=\frac{\sqrt{3}}{4}(5x)^2=\frac{25\sqrt{3}}{4}x^2$

The area within circle and outside the triangle would be difference of area of circle and triangle as:

$A(x)=\frac{25\pi x^2}{3}-\frac{25\sqrt{3}x^2}{4}$

We can make a common denominator as:

$A(x)=\frac{4\cdot 25\pi x^2}{12}-\frac{3\cdot 25\sqrt{3}x^2}{12}$

$A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}$

Therefore, our required expression would be $A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}$ .

7 0

3 years ago

Afton made a chicken dish for dinner. She added a 10 ounce package of vegetables and a 14 ounce package of rice to a 40 ounces o

uysha [10]

Answer:

4 lb

Step-by-step explanation:

10+14+40=64 oz = 4lb

7 0

4 years ago

Read 2 more answers