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BlackZzzverrR [31]
3 years ago
7

You’re looking at the apple pie nutrition label above. Find the number of calories in 1 g. Use the calories in a serving in the

grams in a serving to figure this out. Show your work and answer with a sentence in correct units round to the nearest 10th of a gram
Mathematics
1 answer:
Serggg [28]3 years ago
8 0

Answer i think 588

Step-by-step explanation:

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I'm having trouble on ixl here is what I have to do
Sophie [7]

Answer:

6(9r-7)

Step-by-step explanation:

54r–42

Both 54 and 43 can be divided by 6

54/6 =9  and 42/6 =7

6*9r - 6*7

Factor out the 6

6(9r-7)

8 0
3 years ago
Read 2 more answers
It is known that IQ scores form a normal distribution with a mean of 100 and a standard deviation of 15. If a researcher obtains
sdas [7]

Answer:

X \sim N(100,15)  

Where \mu=100 and \sigma=15

We select a sample of n=16 and we are interested on the distribution of \bar X, since the distribution for X is normal then we can conclude that the distribution for \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Because by definition:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

E(\bar X) = \mu

Var(\bar X) = \frac{\sigma^2}{n}

And for this case we have this:

\mu_{\bar X}= \mu = 100

\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(100,15)  

Where \mu=100 and \sigma=15

We select a sample of n=16 and we are interested on the distribution of \bar X, since the distribution for X is normal then we can conclude that the distribution for \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Because by definition:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

E(\bar X) = \mu

Var(\bar X) = \frac{\sigma^2}{n}

And for this case we have this:

\mu_{\bar X}= \mu = 100

\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75

6 0
3 years ago
Please answer with work!
Arlecino [84]
4 is a solution to the equation. It is true.

3 0
3 years ago
{ x + y = 158<br> x- y = 112
ZanzabumX [31]

Answer:

i have know

Step-by-step explanation:

3 0
3 years ago
Mrs. perry hires a landscaper that charges $15 per hour. The landscaper says that the total charge for the work Mrs. perry wants
kati45 [8]

120 divided by 15 =8

4 0
4 years ago
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