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Gekata [30.6K]
3 years ago
12

Need some help................

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

its option B: r=(3xy)/(x-2y)

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What are the domain and range of the function?<br> f(x) = ^3 square x - 3
DerKrebs [107]

Step-by-step explanation:

f(x) = \sqrt[3]{x - 3}

The domain of a function are the values of x that you can plug into the function f(x).

Values inside of a root must be non-negative, which means that x - 3 must be greater than or equal to zero. We can set up an equation to find the domain:

x - 3 \geq 0

x \geq 3

With this, we know the domain of the function is [3, \inf).

The range of a function are the values that f(x) can have. Since the equation is a cube root, the value will always be non-negative, meaning the range of the function is [0, \inf).

4 0
3 years ago
Find the volume: 65yd 4 yd 13 yd​
max2010maxim [7]

Answer:

3380yd

Step-by-step explanation:

65x13x4

3 0
2 years ago
the equation of a line is y=-1/2x-2. what is the equation of the line that is perpendicular to the first line and passes through
Alexxandr [17]
Perpendicular means that the slopes are negartive inverses, aka
slope1 times slope2=-1

y=mx+b
slope=m

y=-1/2x-2
slope=-1/2

we need to find negative inverse
-1/2 times what=-1
answer is 2

y=2x+b
input the point (2,-2) to find b
(x,y)
(2,-2)
-2=2(2)+b
-2=4+b
minus 4 from both sides
-6=b
y=2x-6

the equtaion is y=2x-6
8 0
3 years ago
Can someone help me draw this out to visualize it?
Vedmedyk [2.9K]

Answer:

Solution given:

South distance :base[b]=80milea

East distance :perpendicular [p]=35miles

Now

<S=?

we have

\tan( \alpha )  =  \frac{p}{b}  =  \frac{35 }{80}

\alpha  =  \tan {}^{ - 1} ( \frac{7}{16} )

\alpha  = 23.629°=24°

24° bearing should be taken from south airport to East airport.

3 0
3 years ago
the volume v of a tank varies directly with its height h a tank 12 ft High holds 300 cubic feet write an equation relating v &am
Liula [17]

v varies directly with height means

v/h=k were k is a constant

or also h/v=k where k is a constant (this is a different k than previous)

so if h=12 and v=300 then

h/v=12/300=1/25=k

so the relationhip could be h/v=1/25


if you di v/h, then

v/h=300/12=25/1=25=k

so the relationship could be v/h=25

3 0
3 years ago
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