Answer:
a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

d.9
b) 
a.15
c) For this case we have the sample size n = 25 and the sample variance is
, the standard error can founded with this formula:

Step-by-step explanation:
Part a
For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

d.9
Part b
From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

And the sample variance for this case can be calculated from this formula:

a.15
Part c
For this case we have the sample size n = 25 and the sample variance is
, the standard error can founded with this formula:

Answer:
(-4,5)
*View attached graph*
Step-by-step explanation:
y = -2x - 3
4y + x = 16
4y + x = 16
4(-2x - 3) + x = 16
-8x - 12 + x = 16
-7x - 12 = 16
+12 + 12
-7x = 28
/-7 /-7
x = -4
4y + x = 16
4y + (-4) = 16
4y - 4 = 16
+ 4 + 4
4y = 20
/4 /4
y = 5
(x,y) -> (-4,5)
Hope this helps!
Answer:
no question pls give and I can think
58*0.71= around 41.2 grams of coco. This is because we can multiply to get this.
Please like and brainiest if correct!