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erma4kov [3.2K]
2 years ago
6

If PQR ~ QST, find the value of x

Mathematics
1 answer:
MaRussiya [10]2 years ago
5 0

Answer:

I don't understand.

Step-by-step explanation:

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The population od  a small country  is 5,740,000. Express this number using scientific notation. Say steps to.
bija089 [108]
5,740,000( you have to make the number less than 10

5.740000 ( you put a decimal to make it less )

5.74e6 (you count how many times you skipped over to get at the decimal point , and that's your awnser .
5 0
3 years ago
David has 16 skate wheels, which he is putting on 4 boards to go with the 3 boards he has. How many boards does he have altogeth
Aleksandr-060686 [28]
He has a total of 7 Boards. he has 3 boards of his own and then you add the 4 additional boards that he has 
4 0
3 years ago
Help on both please ! Im a new student at this school and didn't learn this
larisa86 [58]
For the first one, you have to convert the fractions to an improper fraction. To do that you need to multiply the bottom denominator number (3) by the whole number (1) then you need to add the numinator, so 3x1+2= 5. You have to keep the denominator so 1 2/3 is equal to 5/3. Then do the same to 2 1/5, and you get 11/5. Now you have to find a common denominator, that's basically the smallest number that both numbers can go Into, the lowest common denominator for 3 and 5 is 15. So 3x5= 15, so we have to multiply the top number by 5 which is 25. So 5/3 is equal to 25/15, then 5x3= 15, so you need to multiply 11 by 3 which is 33. So 11/5 is equal to 33/15. Then you add them. Add the numinators (25+33=58. Then you keep the denominator 15. So when u add it it's 58/15 then you need to simplify that and you get 3 13/15.

The second one you turn them into improper fractions like I told you how to before (multiply the bottom number by the whole number then add he top number, then add he same denominator.) do that for both. Then you line them right next to each other and multiply across. (I just realized that they were the same number so they are equal to 5/3 and 11/5)
Then you do 5x11 and you get 55 then do 3x5 and you get 15. 55/15 is your answer, but you need to simplify it, you need to divide 55 by 15, (not all the way just the first number) so you do 15x3 and that's 45, then you subtract that from 55, and you get 10, so then you take your denominator (15) and you answer is 3 10/15. But when you simplify it it's 3 and 2/3


Hope I helped sorry it's so long and sorry for any typos it's so long I didn't go back and check
5 0
3 years ago
15/10 to a mixed number
tensa zangetsu [6.8K]
First, we have to find how many times 10 goes into 15.

We can divide 15 by 10, and we will see that 10 goes into 15 1 whole time, with 5/10 left over.

Now, we can simplify!

In order to simplify, we have to find the GCF (greatest common factor) of 5 and 10. Let's list out the factors (the numbers that can be divided into 5 and 10)

1*5

1*10
2*5

The largest factor, as we can see, is 5! Let's dicide 5/10 by 5.

5/5=1
10/5=2

So, 5/10 simplifies to 1/2, and, if we bring down the whole number we found before, 15/10 is equal to 1 and 1/2! :)

We can check this answer by multiplying the whole number, 1, by the denominator, (the bottom number of a fraction) 2, and adding the numerator, (the top number of a fraction), 1.

1*2=2
2+1=3

Keep the denominator as 2.

The improper fraction is 3/2, which is equivalent to 15/10 (multiply 3/2 by 5 to see)!

So, our answer is 1 1/2.

I hope I helped! :)
3 0
3 years ago
(1+cos2x)/(1-cos2x) = cot^2x
sesenic [268]

We will turn the left side into the right side.

\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x

Use the identity:

\cos 2x = \cos^2 x - \sin^2 x

\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x

\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x

Now use the identity

\sin^2 x + \cos^2 x = 1 solved for sin^2 x and for cos^2 x.

\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x

\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x

\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x

\cot^2 x = \cot^2 x


8 0
3 years ago
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