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IgorLugansk [536]
3 years ago
14

A bus travels with a constant speed of 48 miles per hour. How long will it take to travel 60 miles?

Mathematics
1 answer:
andre [41]3 years ago
4 0

Answer:

A bus travels with a constant speed of 48 miles per hour. How long will it take to travel 60 miles?

Step-by-step explanation:

Mostly it's 1.25 hours </3 Since distance = rate times , or d = rt, then we have

t = d/r = 60 miles / 48 mph = 1.25 hours = 1 hour 15 minutes

either 1 hour 15 mins or 1hour and 25 mins.

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1,8,55 what is the answer
Gemiola [76]

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Find the slope given The following point (12,-2) and (4,-6)
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The slope of the equation is 1/2
6 0
3 years ago
Solve for x, then find the perimeter. You should select TWO answer choices.
dimulka [17.4K]

Answers:

x = 6 and P = 128

=================================================================

Explanation:

The tangents CT and CU are equal to each other. The rule is that tangent segments that meet at a common point are the same length.

Let's solve for x

CT = CU

3x = 18

x = 18/3

x = 6

Because CT = 18, this makes BC = BT+TC = 12+18 = 30

---------------------------

For similar reasoning as mentioned earlier, we can say tangents BT and BV are the same length. This means BV = 12.

Segment CD = 52 and CU = 18, which makes UD = CD-CU = 52-18 = 34

From there, we can say segment DV = 34 also. This leads to BD = BV+VD = 12+34 = 46

Triangle BCD has the three sides

  • BC = 30
  • CD = 52
  • BD = 46

The perimeter is

P = sum of the three sides

P = (side1)+(side2)+(side3)

P = BC + CD + BD

P = 30+52+46

P = 82+46

P = 128

7 0
3 years ago
After the release of radioactive material into the atmosphere from a nuclear power plant in a country in 1982​, the hay in that
galina1969 [7]

Answer:

25.48 days

Step-by-step explanation:

For a radioactive substance, the Amount of the substance remaining A(t) is modeled by the equation

A(t)=A_0(\dfrac{1}{2})^{\dfrac{t}{t_{1/2}} }

where

A_0 =$Initial Amount$\\t_{1/2}=$Half-Life of the Substance$\\t=$Time elapsed$

In the given problem:

Half Life of the Radioactive Isotope = 8

Initial Amount, A_0=100%=1

A(t)=11% =0.11

Therefore substituting in the model above:

0.11=1(\dfrac{1}{2})^{\dfrac{t}{8} }\\0.11=0.5^{t/8}\\$Change to Logarithm form$\\Log_{0.5}0.11=\frac{t}{8}\\\frac{Log 0.11}{Log 0.5} =\frac{t}{8}\\3.1844=\frac{t}{8}\\t=8X3.1844=25.4752

The farmer need to wait for 25.48 days

4 0
3 years ago
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