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katen-ka-za [31]
3 years ago
5

What is the domain and range for following graph

Mathematics
2 answers:
ziro4ka [17]3 years ago
7 0
Domain {-2,2}
Range {-3,3}
ExtremeBDS [4]3 years ago
3 0

Step-by-step explanation:

Domain is [-2;2]

Rangeis [-3;3]

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Pls help i am in k12 i will mark the brainlyest
olga55 [171]

Step-by-step explanation:

hi I'm in K12 too and this looks like a tga

5 0
3 years ago
A tower casts a shadow 11 feet long the distance from the top of the tower to the end of the the shadow is 61 feet how many feet
Jobisdone [24]
This is very easy!! I have attached a picture I have drawn if you are a visual learner... well, everything else like computations is here. 
.
This is the PYTHAGOREAN THEOREM!!
.
If you don't know, it says that the lengths of the legs squared added together all equal the hypotenuse squared in a right triangle!!
.
And if you want to know why the "triangle" has a right angle... well,  are towers slanted? I mean, other than the Leaning Tower of Pizza. I mean Pisa.
.
So... we plug it in!!
.
Formula: a^2 + b^2 = c^2.
.
Plug it in: 11^2+ 61^2 = c^2
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c^2 = 3842.
.
So now what?
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SQUARE ROOT OF EVERYTHING!!
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c = <span>√3842.
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So? c = approximately 61.984.
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Hope I helped!!</span>

8 0
3 years ago
Which of the following is a correct conversion of 50 kg
wariber [46]

Answer:

c. 50kg = 50,000g

Step-by-step explanation:

We have to solve these following rule of three to see which of the following is a correct conversion of 50kg.

a)

Each kg has 1000g

So

1kg - 1000g

50kg - xg

x = 50*1000

x = 50,000g

Conversion a) is wrong

b)

Each kg has 1000000mg

So

1kg - 1000000g

50kg - x mg

x = 50*1000000

x = 50,000,000 mg

Conversion b) is wrong

c)

In a), we have already converted 50kg to g. We have verified that 50kg = 50,000g. So c. is correct

d)

In b), we have already converrted 50kg to mg. We have verified that 50kg = 50,000,000g. So d. is wrong

4 0
3 years ago
BRAINLIESTT ASAP! PLEASE HELP ME :)
sweet [91]

\displaystyle y = Atan(Bx - C) + D

According to this <em>trigonometric function</em>, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL.

Extended Information on the trigonometric function

\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{π}{B} \\ Amplitude → |A|

NOTE: Sometimes, your <em>vertical</em><em> </em><em>shift</em><em> </em>might tell you to extend the troughs on each end of your graphs, beyond the <em>midline</em>.

* All tangent functions have NO AMPLITUDES.

I am joyous to assist you anytime.

6 0
3 years ago
10 points
vichka [17]

Answer:

i need the answer aswell

6 0
3 years ago
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