Step-by-step explanation:
hi I'm in K12 too and this looks like a tga
This is very easy!! I have attached a picture I have drawn if you are a visual learner... well, everything else like computations is here.
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This is the PYTHAGOREAN THEOREM!!
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If you don't know, it says that the lengths of the legs squared added together all equal the hypotenuse squared in a right triangle!!
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And if you want to know why the "triangle" has a right angle... well, are towers slanted? I mean, other than the Leaning Tower of Pizza. I mean Pisa.
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So... we plug it in!!
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Formula: a^2 + b^2 = c^2.
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Plug it in: 11^2+ 61^2 = c^2
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c^2 = 3842.
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So now what?
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SQUARE ROOT OF EVERYTHING!!
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c = <span>√3842.
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So? c = approximately 61.984.
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Hope I helped!!</span>
Answer:
c. 50kg = 50,000g
Step-by-step explanation:
We have to solve these following rule of three to see which of the following is a correct conversion of 50kg.
a)
Each kg has 1000g
So
1kg - 1000g
50kg - xg
x = 50*1000
x = 50,000g
Conversion a) is wrong
b)
Each kg has 1000000mg
So
1kg - 1000000g
50kg - x mg
x = 50*1000000
x = 50,000,000 mg
Conversion b) is wrong
c)
In a), we have already converted 50kg to g. We have verified that 50kg = 50,000g. So c. is correct
d)
In b), we have already converrted 50kg to mg. We have verified that 50kg = 50,000,000g. So d. is wrong

According to this <em>trigonometric function</em>, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{π}{B} \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B%CF%80%7D%7BB%7D%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your <em>vertical</em><em> </em><em>shift</em><em> </em>might tell you to extend the troughs on each end of your graphs, beyond the <em>midline</em>.
* All tangent functions have NO AMPLITUDES.
I am joyous to assist you anytime.