10 points

Mathematics

1 answer:

vichka [17]2 years ago

6 0

Answer:

i need the answer aswell

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Prove : (sec θ - tan θ )^2 = 1 - sin θ /1+sin θ

labwork [276]

$(sec x - tan x)^2 \\ \\ = sec^2x - 2 sec x tan x + tan^2 x \\ \\ =(1+tan^2 x) - 2 sec x tan x +tan^2 x \\ \\ =1 - 2 sec x tan x + 2 tan^2 x \\ \\ = 1 - 2tan x(sec x - tan x) \\ \\ =1 - \frac{2 sin x}{cos x} (\frac{1-sin x}{cos x}) \\ \\ = 1 - \frac{2 sin x (1-sin x)}{cos^2 x} \\ \\ =1 - \frac{2 sin x (1-sin x)}{1-sin^2 x} \\ \\ =1 - \frac{2 sin x (1-sin x)}{(1-sin x)(1+sin x)} \\ \\ =1-\frac{2 sin x}{1+sin x}$

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2 years ago

A map has a scale of

givi [52]

For ever 4 inches, you have 25 miles. Therefore if you have only one, you multiply to find the other. Now, since you have miles, you need to find inches. Therefore, 120 divided by 4, because every 4 inches is equal to 25 miles. Your answer should be 30 inches

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3 years ago

Which equation could represent the graph shown below?

almond37 [142]

Answer:

y= $-\sqrt{x-2}$