Answer:
Bag of windflower bulbs costs $8.50
Package of crocus bulbs costs $17.60
Step-by-step explanation:
Let $x be the price of one bag of windflower bulbs and $y be the price of one package of crocus bulbs.
1. Mark sold 2 bags of windflower bulbs for $2x and 5 packages of crocus bulbs for $5y. In total he earned $(2x+5y) that is $105. So,
2x+5y=105
2. Julio sold 9 bags of windflower bulbs for $9x and 5 packages of crocus bulbs for $5y. In total he earned $(9x+5y) that is $164.50. So,
9x+5y=164.50
3. You get the system of two equations:
From the first equation
Substitute it into the second equation:
9x+105-2x=164.50
7x=164.50-105
7x=59.5
x=$8.50
So,
5y=105-2·8.5
5y=105-17
5y=88
y=$17.60
Answer:
Step-by-step explanation:
We can use exponent rules to try and simplify this expression down.
Exponent rules tell us that 
.
This means that since we have the same base on both terms (7 and 7), we can add the exponents to get a simplified expression.
So our simplified expression is 
.
Hope this helped!
Answer:
1. C. Yes, because a sum of cubes can be factored
2a. false
2b. false
2c. true
2d. false (based on what is written in the equation; refer to step-by-step)
Step-by-step explanation:
1. Both 3 and 8 can be cubed, which is why x^3+8 can be factored (x+2)(x^2-2x+4)
2a. a^2-b^2 can be factored by the perfect square rule, so it should be (a-b)^2
2b. both terms are perfect squares, so you can factor, making it (a+b)(a-b)
2c. You can factor using the perfect square rule, making it (a+b)^2
2d. Most of what is in the equation is true, yet the correct solution would be (a-b)(a^2+ab+b^2)
Answer:
wow
Step-by-step explanation:
Fatima's claim is not supported by the table because, the distribution is skewed right, with a median of 0.4 field goal advantage.
From the table, the median position is calculated as:
The 0.2nd data falls in the 0.4 field goal category.
So, the median element is:
However, the distribution of the table are concentrated on the left.
This means that, the distribution is not uniform, instead it is skewed right.
A uniform distribution has a skewness of 0.
Hence, Fatima's claim is not supported by the table
Read more about distributions at:
brainly.com/question/13233983
