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erastova [34]
3 years ago
8

Wilson wants to know how long it will take his $1000 investment to double

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
7 0

Answer:

Step-by-step explanation:

Take the log of both sides:

log(2) = t*log 1.015, so that:

        log(2)

t = --------------- = 46.6 compounding periods, which is 46.6/4, or 11.6 years

     log 1.015

Can't write this exponential equation as a logarithm; instead, CAN write it in logarithmic form.

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Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come f
AlladinOne [14]

Answer:

z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43  

Now we can calculate the p value with the following probability:

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Step-by-step explanation:

Data given and notation

n=75 represent the random sample taken

\hat p=0.64 estimated proportion of interest

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if the true proportion is higher than 0.5:  

Null hypothesis:p =0.5  

Alternative hypothesis:p > 0.5  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{75}}}=2.43  

Now we can calculate the p value with the following probability:

p_v =P(z>2.43)=0.0075 \approx 0.008  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportion for this case is higher than 0.5

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