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emmasim [6.3K]
3 years ago
6

A $5000 principal is invested in two accounts, one earning 1% interest and the another earning 6% interest. If the total interes

t for the year is $170, then how much is invested in each account?
Mathematics
1 answer:
algol [13]3 years ago
4 0

Answer: in the 1% account we have $2600 and in the 6% account we have $2400.

Step-by-step explanation:

We have two amounts A and B such that:

Where A is the amount invested in the 1% earning interest account and B is the amount invested in the 6% earning interest account.

A + B = $5000,

If the interest is yearly, then we have that, after one year, the interest is:

A*(1%/100%) + B*(6%/100%) = $170

A*0.01 + B*0.06 = $170

So we have two equations:

A + B = $5000

A*0.01 + B*0.06 = $170

In the first equation we can isolate A and get:

A = $5000 - B

and replace it in the other equation:

($5000 - B)*0.01 + B*0.06 = $170

$50 + B*0.05 = $170

B*0.05 = $120

B = $120/0.05 = $2400

Then A = $5000 - $2400 = $2600.

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B. 14/21

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3 years ago
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What equation is equivalent to 2^3^x =10
Tresset [83]

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<h3>how to find</h3>

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<h3>part 1</h3>

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6 0
2 years ago
On A piece of paper graph the system of equations. Then determine which answer choice matches the graph you drew and identify a
hodyreva [135]

Answer:

Final graph is attached.

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Step-by-step explanation:

As we have to solve by graphing to let's graph y=2x-1 first.

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SSSSS [86.1K]
Hello! 

Ok so ideally we would like to see this in y=mx+b form. But it will take some algebreic skills to ninja our way through this. 

I'll show my steps so you can follow, 

3+4x = 2y - 9 (original equation) 

Next we just add 9 to both sides, 

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7 0
3 years ago
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