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forsale [732]
3 years ago
5

I need help, if is right I mark you as brainliest.

Mathematics
2 answers:
borishaifa [10]3 years ago
5 0

Answer:

D. He distributed -5 incorrectly.

Step-by-step explanation:

Last option is the correct answer.

Arada [10]3 years ago
3 0

Answer:

Parker: D. He distributed -5 incorrectly.

Step-by-step explanation:

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A crate contains cylindrical cans of soup for shipment. Each crate is a cube with side lengths of 12in. Each soup can is 5in tal
denpristay [2]
The volume of the cube is base times width times height, or any of these measurements cubed, since they're all the same. 
Therefore, the volume of the cube is:
 12³ = 1728 in³
The volume of the cylinder is π*r²*h, where r is the radius and h is height
Remember that the diameter is twice the radius, so the radius is 2 in and the height is 5 in. 
Therefore, each can has a volume of π * 2² * 5 = 20π
Approximating π as 3.14....
The volume of each can is 62.8 in³
1728 ÷ 62.8 = 27.5
Rounding down, 27 cans can fit in the crate.
This is how I suspect the teach wanted you to solve, since it involves finding the volume of both shapes and using pi. However, this is not actually how many cans can fit, because it does not take into account the fact that not every inch of available space will be used. 

Here is another way to solve,taking this fact into account, that gives the more accurate answer:

Each can has a diameter of 4in, which means that they each require a square of 4 x 4 in to accommodate their base.
The base of each can requires 16 in² of space in the crate. 
The base of the cube is 12 x 12, so the area of the base is 144 in²
144 ÷ 16 = 9, so the base of the cube, or bottom of the box, can fit 9 cans, arranged 3 by 3. 

The cube has a height of 12 inches, and each can is 5 inches tall. Therefore, two of these stacks can fit in the box, for 9 x 2 = 18 cans. 
This is a much better answer, as it takes into account the fact that the cans can't occupy every inch of available space in the cube. 
5 0
4 years ago
Express it in slope-intercept form.
mrs_skeptik [129]

Answer:

y=3/4x+2

Step-by-step explanation:

The slope intercept formula is y=mx+b

b=2 because it is the y intercept

m is the slope

from (0,2) I counted how many points over and up the next point directly on the two lines was , which was point (4,5)

it was 4 to the right and 3 up

slope is rise over run so the slope is 3/4

5 0
4 years ago
I need help ASAP people :-)
ladessa [460]
12.5 - 8.5 = 4

4/12.5 = 0.32

0.32 • 100 = 32

Answer: 32%
4 0
3 years ago
Eliza started her savings account with $100. Each month she deposits $25 into her account. Write the function that describes the
Stells [14]
Okay, since she started with $100, then that would be a constant. So the function would start off with f(x)=?+100. Okay, now since she is depositing $25 PER month, then the 'x' varibale would be per month. So the function would be f(x)=25x+100. Now since you want to know the rate of change, just insert the x value as the month. For example, you want to know how much money she has on the 4th month, so you would substitute 4 with x --> f(x)=25(4)+100, which is f(x)=200
5 0
3 years ago
Charlie reads quickly. He reads 1\dfrac371 7 3 ​ 1, start fraction, 3, divided by, 7, end fraction pages every \dfrac23 3 2 ​ st
OLEGan [10]
<h2>Answer:</h2>

The number of pages he will read in one minute is:

        2\dfrac{1}{7}\ \text{pages}

<h2>Step-by-step explanation:</h2>

It is given that:

Charlie reads 1\dfrac{3}{7}\ \text{pages} in every \dfrac{2}{3}\ \text{minutes}.

We know that:

1\dfrac{3}{7}=\dfrac{10}{7}

This means that:

Charlie reads \dfrac{10}{7}\ \text{pages} in every \dfrac{2}{3}\ \text{minutes}.

This means that:

\text{In}\ \dfrac{2}{3}\ \text{minutes he reads}\ \dfrac{10}{7}\ \text{pages}\\\\\text{Hence}

\text{In}\ 1\ \text{minute he will read}\ \dfrac{\dfrac{10}{7}}{\dfrac{2}{3}}\ \text{pages}

\text{In}\ 1\ \text{minute he will read}\ \dfrac{10\times 3}{7\times 2}\ \text{pages}

Hence,

\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}

Hence,

\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}

\text{In}\ 1\ \text{minute he will read}\ 2\dfrac{1}{7}\ \text{pages}

4 0
3 years ago
Read 2 more answers
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