What's the sum of 14,12,8,and 6

It said i need to simplify. how do i

horrorfan [7]

Answer:

The equation relating the volume of water, y to the volume of flour, x is therefore;

y = 1/3×x

The quantity of water per liter of flour = 1/3 liters

The quantity of flour per liter of water = 3 liters

Step-by-step explanation:

The given information from the graph are;

At 0 liters of water, the volume of flour = 0 liters of flour

At 1 liter of water, the volume of flour = 3 liters of flour

The relationship between the volume of water and flour is linear given s follows;

The equation for a linear relationship is y = m·x + c

m = The gradient or slope of the line, c = the y-intercept

In the graph the y-intercept = 0 therefore, c = 0

The slope, m is (change in y-coordinate)/(Change in x-coordinate)

∴ m = (1 - 0)/(3 - 0) = 1/3

The equation relating the volume of water, y to the volume of flour, x is therefore;

y = 1/3×x

Such that when the question asks, how many liter of water is used per liter of flour, we get;

y = 1/3× 1 = 1/3 liters

Similarly when the question asks, how many liter of flour is used per liter of water, we get;

1 = 1/3×x

x = 3 × 1 = 3 liters.

4 0

3 years ago

In a hospital there are 56 TB patients. The patients are grouped with respect to their ages.

zalisa [80]

<span>Table:

Class Boundaries         Frequency

5-10                              8

10-15                            9

15-20                          15

20-25                          10

25-30                           8

30-35                           6
                                ----------
total                           56

Average =

[5+10]/2*8+[10+15]/2*9+[15+20]/2*15+[20+25]/2*10+[25+30]/2*8+[30+35]/2*6
---------------------------------------------------------------------------------------------------
</span>                                  56

That is 1075 / 56 = 19.2

Answer: 19

5 0

3 years ago

The function f is defined by the following rule.

Leno4ka [110]

X= -4; f(x)= -15
X= 2; f(x)= 3
X=5; f(x)= 12

6 0

3 years ago

Find e^cos(2+3i) as a complex number expressed in Cartesian form.

ozzi

Answer:

The complex number $e^{\cos(2+31)} = \exp(\cos(2+3i))$ has Cartesian form

$\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2)$ .

Step-by-step explanation:

First, we need to recall the definition of $\cos z$ when $z$ is a complex number:

$\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}$ .

Then,

$\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}$ . (I)

Now, recall the definition of the complex exponential:

$e^{z}=e^{x+iy} = e^x(\cos y +i\sin y)$ .

So,

$e^{2i-3} = e^{-3}(\cos 2+i\sin 2)$

$e^{-2i+3} = e^{3}(\cos 2-i\sin 2)$ (we use that $\sin(-y)=-\sin y)$ .

Thus,

$e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)$

Now we group conveniently in the above expression:

$e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2$ .

Now, substituting this equality in (I) we get

$\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2$ .

Thus,

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)$

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right]$ .

5 0

3 years ago

Can I get help with this? Thanks!

Keith_Richards [23]

X=hamburgers
y=hotdogs

3y+2x=8.00
AND
2y+3x=8.25

Now we've got a system of equations!

Choose a method to solve it, and I think you'll be good from there.

If you need more guidance to the answer, tell me in the comments.

BEST OF LUCK:)

6 0

3 years ago

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