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Gala2k [10]
3 years ago
13

Over the past month, a garment manufacturer produced 800 dresses. The distribution of the amount of fabric required to make the

dresses is
not normal.

The average amount of fabric needed to make a dress is 4 yards, with a standard deviation of 2 of a yard. Suppose a series of samples, each

containing 180 dresses, are selected from the dresses produced in the past month.

Would it be appropriate to model the distribution of a sample mean with a normal model?
Mathematics
2 answers:
son4ous [18]3 years ago
6 0

Answer:

Yes it will be appropriate to model the distribution of a sample mean with a normal model

Step-by-step explanation:

Given that the population is not normal, and the sample is sufficiently large, according to the Central Limit theorem, the distribution of the mean pf the sampling distribution will be approximately normal not withstanding the population from which the sample is obtained. Therefore, the mean, \overline x, and the standard deviation, \dfrac{\sigma}{\sqrt{n} }, of the sample will be equal to the mean, μ, and standard deviation, σ, of the of the population

Therefore, it will be appropriate to model the distribution of a sample mean with a normal model

slavikrds [6]3 years ago
6 0

Answer:

yes

Step-by-step explanation:

i got it right on plato

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Vesnalui [34]

Answer:

The required expression is 3.5-k

Step-by-step explanation:

Given : Statement 'k less than 3.5'.

To find : Write an expression to show statement ?

Solution :

According to statement,

Statement 'k less than 3.5'.

Less than means the number is subtracted from another number.

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For this tangent line approximation question, my answer is D. 4. Is my work correct?
tamaranim1 [39]
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If you wanted, you can simplify the linear approximation L(x) 
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L(x) = f(-0.5) + (x-(-0.5))*f'(-0.5)
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sleet_krkn [62]

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Step-by-step explanation:

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