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Vladimir [108]
3 years ago
5

See attachment for the whole question.

Mathematics
1 answer:
KengaRu [80]3 years ago
7 0

Using probability concepts, it is found that:

a) \frac{4}{13} probability of drawing a card below a 6.

b) \frac{4}{9} odds of drawing a card below a 6.

c) We should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.

------------------------------

  • A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.

Item a:

  • In a standard deck, there are 52 cards.
  • There are 4 types of cards, each numbered 1 to 13. Thus, 4 \times 5 = 20 are less than 6.

Then:

p = \frac{20}{52} = \frac{4}{13}

\frac{4}{13} probability of drawing a card below a 6.

Item b:

  • Converting from probability to odd, it is:

\frac{4}{13 - 4} = \frac{4}{9}

\frac{4}{9} odds of drawing a card below a 6.

Item c:

  • The law of large numbers states that with a <u>large number of trials, the percentage of each outcome is close to it's theoretical probability.</u>
  • Thus, we should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.

A similar problem is given at brainly.com/question/24233657

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