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3 years ago

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A photo of an ant in a science book is increased to 618% as large as the actual size. If the ant is 15 millimeter, what is the s

ize of the ant in the photo?

1 answer:

irakobra [83]3 years ago

3 0

Answer:

92.7?????

Step-by-step explanation:

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If you are buying at item at a store for a price of $74, and there is a 5.9% tax added on top, what would be the total amount du

Lemur [1.5K]

Answer:

I don't know the real answer is 78.366 so it's either $78.36 or $78.37. You didn't say round it so I would go with $78.36 as my final answer.

Step-by-step explanation:

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3 years ago

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Need help rn plzzzzzz

bagirrra123 [75]

Answer:

10,30

Step-by-step explanation:

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3 years ago

HELP ASAP PLEASE!!! worth 20 points!!

lukranit [14]

No, because the height of the boat is 2.1+8.7=10.8
after the boat is lifted, it’s 1.3 feet above the ground in which is addition to the total height the boat will take up. 10.8+1.3=12.1 feet.

4 0

4 years ago

A coin is flipped eight times where each flip comes up either heads or tails. How many possible outcomes a) are there in total?

attashe74 [19]

Answer:

There are 256 ways in total.

There are 56 possible outcomes contain exactly three heads.

The possible outcomes contain at least three heads is 219.

The possible outcomes contain the same number of heads and tails are 70.

Step-by-step explanation:

Consider the provided information.

A coin is flipped eight times where each flip comes up either heads or tails.

Part (a) How many possible outcomes are there in total?

Each time we flip a coin it comes up either heads or tail.

Therefore the total number of ways are:

$2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=2^8=256$

Hence, there are 256 ways in total.

Part (b) contain exactly three heads?

We want exactly 3 heads, therefore,

n=8 and r=3

According to the definition of combination: $\binom{n}{r}=\frac{n!}{r!(n-r)!}$

$\binom{8}{3}=\frac{8!}{3!(5)!}=56$

Hence, there are 56 possible outcomes contain exactly three heads.

Part (c) contain at least three heads?

For 3 heads: $\binom{8}{3}=\frac{8!}{3!(5)!}=56$

For 4 heads: $\binom{8}{4}=\frac{8!}{4!(4)!}=70$

For 5 heads: $\binom{8}{5}=\frac{8!}{5!(3)!}=56$

For 6 heads: $\binom{8}{6}=\frac{8!}{6!(2)!}=28$

For 7 heads: $\binom{8}{7}=\frac{8!}{7!(1)!}=8$

For 8 heads: $\binom{8}{8}=1$

Now add them as shown:

56+70+56+28+8+1=219

Hence, the possible outcomes contain at least three heads is 219.

Part (d) contain the same number of heads and tails?

Same number of heads and tails means that the value of r=4.

Therefore,

$\binom{8}{4}=\frac{8!}{4!(4)!}=70$

Hence, the possible outcomes contain the same number of heads and tails are 70.

6 0

3 years ago

A B C or D? Multiple choice please help

S_A_V [24]

Answer: a

Step-by-step explanation:

(6z³+3z²-4z+8) - (4z²-3z+2)

all of the numbers in the second set of parenthesis are going to have their signs switched so...

(6z³+3z²-4z+8) + (-4z²+3z-2)

now you add the two sets of parenthesis

<u>6z³ - z² - z + 6</u>

<u />

7 0

3 years ago