1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
butalik [34]
3 years ago
13

Suppose the speeds of cars along a stretch of I-40 is normally distributed with a mean of 70 mph and standard deviation of 5 mph

. Use the 68-95-99.7 rule to answer the following questions.
(a) Approximately what percent of cars are travelling between 65 and 75 mph? percent
(b) If the speed limit on this stretch of highway is 65 mph, approximately what percent of cars are traveling faster than the speed limit? percent
(c) What percent of cars are traveling at a speed greater than or equal to 80 mph? (Answer to one decimal place.)
(d) What percent of cars are traveling at a speed greater than 80 mph? (Answer to one decimal place.) percent
(e) 95% of cars are traveling between what two speeds? (Answer to two decimal places) Between mph and mph
Mathematics
1 answer:
neonofarm [45]3 years ago
6 0

Answer:

a) 68%.

b) 84%.

c) Approximately 2.5% of cars are traveling at a speed greater than or equal to 80 mph.

d) Approximately 2.5% of cars are traveling at a speed greater than or equal to 80 mph.

e) Between 60 mph and 80 mph.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 70 mph, standard deviation of 5 mph.

(a) Approximately what percent of cars are travelling between 65 and 75 mph?

70 - 5 = 65

70 + 5 = 75

Within 1 standard deviation, so approximately 68%.

(b) If the speed limit on this stretch of highway is 65 mph, approximately what percent of cars are traveling faster than the speed limit?

The normal distribution is symmetric, which means that 50% of the measures are below the mean, and 50% are above.

65 is one standard deviation below the mean, so of the cars below the mean, 68% are above 65 mph.

0.68*50% + 50% = 34% + 50% = 84%.

84%.

(c) What percent of cars are traveling at a speed greater than or equal to 80 mph?

80 = 70 + 2*10

2 standard deviations above the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean. Due to the symmetry of the normal distribution, of the other 5%, 2.5% is at least 2 standard deviations below the mean and 2.5% is at least 2 standard deviations above the mean. Then:

Approximately 2.5% of cars are traveling at a speed greater than or equal to 80 mph.

(d) What percent of cars are traveling at a speed greater than 80 mph?

Same as item c, as in the normal distribution, the probability of an exact value is considered to be 0.

(e) 95% of cars are traveling between what two speeds?

Within two standard deviations of the mean.

70 - 2*5 = 60 mph

70 + 2*5 = 80 mph.

Between 60 mph and 80 mph.

You might be interested in
Your gross weekly salary is $800.00. Your federal income tax deduction is $53. The Social Security tax is 6.2%. The Medicare tax
lord [1]
Make an equation for this find the variables P and t and 200. Them plug the into an equation like y=mx+b.
6 0
3 years ago
Which the following segments is a diameter of o.
Kazeer [188]

p-by-step exe right answer

Stplanation:Answer:

B is the

6 0
3 years ago
Read 2 more answers
April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3
vlada-n [284]

Answer:

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = 5\frac{1}{4}\ hrs

5\frac{1}{4}\ hrs can be Rewritten as \frac{21}{4}\ hrs

Number of Hours Carl worked on Math project = \frac{21}{4}\ hrs

Number of Hours Sonia worked on Math project = 6\frac{1}{2}\ hrs

6\frac{1}{2}\ hrs can be rewritten as \frac{13}{2}\ hrs

Number of Hours Sonia worked on Math project = \frac{13}{2}\ hrs

Number of Hours Tony worked on Math project = 5\frac{2}{3}\ hrs

5\frac{2}{3}\ hrs can be rewritten as \frac{17}{3}\ hrs.

Number of Hours Tony worked on Math project = \frac{17}{3}\ hrs.

Now Given:

April worked 1\frac{1}{2} times as long on her math project as did Carl.

1\frac{1}{2}  can be Rewritten as \frac{3}{2}

Number of Hours April worked on math project = \frac{3}{2} \times Number of Hours Carl worked on Math project

Number of Hours April worked on math project = \frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs

Also Given:

Debbie worked 1\frac{1}{4} times as long as Sonia.

1\frac{1}{4}  can be Rewritten as \frac{5}{4}.

Number of Hours Debbie worked on math project = \frac{5}{4} \times Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = \frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs

Also Given:

Richard worked 1\frac{3}{8} times as long as tony.

1\frac{3}{8} can be Rewritten as \frac{11}{8}

Number of Hours Richard worked on math project = \frac{11}{8} \times Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = \frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs

Hence We will match each student with number of hours she worked.

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

5 0
3 years ago
Read 2 more answers
Which expression is equivalent to -6(3x- 2/3)?
Anestetic [448]

Answer: −18x+4

Step-by-step explanation:  

=(−6)(3x+ −2/3)

=(−6)(3x)+(−6)(

−2/3)

5 0
3 years ago
The percent decrease of an item that dropped in price from $50 to $43 is​
frez [133]

Answer:

14%

Step-by-step explanation:

The item dropped from $50 to $43 .

Therefore,

Decrease = $50 - $43

= $7

To get the % decrease, divide the decrease by the initial price and multiply the result by 100%

That’s

$7/$50 x 100%

$0.14 x 100%

= 14%

The price of the item decreased by 14%

5 0
3 years ago
Read 2 more answers
Other questions:
  • If a man earns £80,000 a week and this is 900% more than he used to earn, what was his original wage?
    8·2 answers
  • Monica need to but soup. the store has- 5 cans for $10.00. is she buys just one can of soup, the cost is $2.20 Which is the bett
    15·2 answers
  • Write the equation of a circle.
    6·1 answer
  • A Roth IRA is advertised to pay 1.5% annual interest. You researched the rate of inflation to be 1.15% this year. What is the ac
    10·1 answer
  • .........................
    8·1 answer
  • $24,000 at 5% for 5 years . $_
    14·1 answer
  • I am an odd number between 10 and 20. I can be divided by 3. What number am I?
    8·2 answers
  • I am doing home<br> work and need help due day
    10·1 answer
  • 20. Find the solution to the system of linear equations below:
    6·1 answer
  • Choose the numbers that are irrational
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!