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Solnce55 [7]
2 years ago
14

Between what two integers is √70?

Mathematics
1 answer:
mel-nik [20]2 years ago
6 0

Answer:

8 and 9

Step-by-step explanation:

8^2 is 64 and 9^2 is 81 so 8 and 9

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How to find the mean of 2, 7, 6, 1, 9, 2, 4, 9
Lady_Fox [76]

Answer:

5

Step-by-step explanation:

Add the numbers together, then divide that by the amount of numbers

(2 + 7 + 6 + 1 + 9 + 2 + 4 + 9)/8

40/8 = 5

6 0
2 years ago
How can you make 64, multiplying just two numbers?
Darina [25.2K]

These are all the answers to this question!

1 x 64 = 64

2 x 32 = 64

4 x 16 = 64

8 x 8 = 64

16 x 4 = 64

32 x 2 = 64

64 x 1 = 64

7 0
3 years ago
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Hannah placed 42,000
hammer [34]
Hannah.............. :)
3 0
3 years ago
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Fiona wrote out the description of each step for her multiplication of the binomial and trinomial (2x – 3)(5x2 – 2x + 7).
Arte-miy333 [17]
I just took the test and the answer is step 2.
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3 years ago
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78 : 120 :: ? : 66<br>please give answer with explanation<br>​
yawa3891 [41]

Step-by-step explanation:

<u>Method</u><u> </u><u>1</u><u>:</u>

Given that:

78 : 120 :: ? : 66

Here,

Product of extremes = 78 and 66

Product of means = 120 and ?

so,

(78*66) = (120 * ?)

⇛5148 = 120 * ?

⇛5148 = 120?

⇛120? = 5148

Shift the number 120 from LHS to RHS, changing it's sign.

⇛? = 5148/120

Therefore, (?) = 42.9

<u>Method</u><u> </u><u>2</u><u>:</u>

78 : 120 :: ? : 66

Convert each ratio into fraction.

⇛78/120 = ?/66

On applying cross multiplication then

since, (a/b) = (c/d) ⇛cd = ad

Where, a = 78, b = 120, c = ? and d = 66

Now,

⇛(120)? = (78)66

⇛120? = 5148

⇛(?) = 5148/120

Therefore, (?) = 42.9

<u>Ans</u><u>w</u><u>er:</u> Hence the value of (?) for the given problem is 42.9.

<u>Verification</u><u>:</u>

Check whether the value of (?) is true or false.

78 : 120 :: ? : 66

Substitute the value of (?).

⇛78:120 = 42.9:66

Product of extremes should be equal to product of means.

Product of extremes:- 78*66 = 5148

Product of means:- 120*42.9 = 5148

⇛5148 = 5148

LHS = RHS

Hence, verified.

4 0
2 years ago
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