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3 years ago

Between what two integers is √70?

Mathematics

1 answer:

mel-nik [20]3 years ago

6 0

Answer:

8 and 9

Step-by-step explanation:

8^2 is 64 and 9^2 is 81 so 8 and 9

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What is the mean absolute deviation of 10 16 18 15 15 10 23

grigory [225]

The answer is 3.1428 (very close to π actually lol)

4 0

3 years ago

Read 2 more answers

Worth 10 of 50 points, help!

Elina [12.6K]

A typical example of a rational exponent and radicals is a^x/y = y√(a)^x

<h3>What is a rational exponent?</h3>

We have a rational exponent when a number is raised to a power such as x/y. In this case, we must know that; a^x/y is the same as y√(a)^x.

Now let me give you a specific example. Assuming that a write something like 5^3/2. This would be the same as saying √(5)^3.

Learn more about rational exponent:brainly.com/question/3009444

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2 years ago

The top question asap

xxTIMURxx [149]

Answer:

A= 50

Step-by-step explanation:

Very interesting to see!

x= -1

and the both angles are equal!

4 0

3 years ago

consider this equation sin(theta) = -4 square root of 29/29 if theta is an angle in quadrant IV what is the value of cos (theta)

MatroZZZ [7]

Answer:

$\cos(\theta)= \frac{\sqrt{377}}{29}$

Step-by-step explanation:

Given

$\sin(\theta) = -\frac{4}{\sqrt{29}}$ -- the correct expression

Required

$\cos(\theta)$

We know that:

$\sin^2(\theta) + \cos^2(\theta)= 1$

Make $\cos^2(\theta)$ the subject

$\cos^2(\theta)= 1 - \sin^2(\theta)$

Substitute: $\sin(\theta) = -\frac{4}{\sqrt{29}}$

$\cos^2(\theta)= 1 - (-\frac{4}{\sqrt{29}})^2$

Evaluate all squares

$\cos^2(\theta)= 1 - (\frac{16}{29})$

Take LCM

$\cos^2(\theta)= \frac{29 - 16}{29}$

$\cos^2(\theta)= \frac{13}{29}$

Take square roots of both sides

$\cos(\theta)= \±\sqrt{\frac{13}{29}}$

cosine is positive in the 4th quadrant;

So:

$\cos(\theta)= \sqrt{\frac{13}{29}}$

Split

$\cos(\theta)= \frac{\sqrt{13}}{\sqrt{29}}$

Rationalize

$\cos(\theta)= \frac{\sqrt{13}}{\sqrt{29}} * \frac{\sqrt{29}}{\sqrt{29}}$

$\cos(\theta)= \frac{\sqrt{13*29}}{29}$

$\cos(\theta)= \frac{\sqrt{377}}{29}$

4 0

3 years ago

A newsletter publisher believes that above 41A% of their readers own a personal computer. Is there sufficient evidence at the 0.

klemol [59]

Complete Question

A newsletter publisher believes that above 41% of their readers own a personal computer. Is there sufficient evidence at the 0.10 level to substantiate the publisher's claim?

State the null and alternative hypotheses for the above scenario.

Answer:

The null hypothesis is $H_o : p \le 0.411$

The alternative hypothesis is $H_a : \mu > 0.41$

Step-by-step explanation:

From the question we are told that

The proportion is $p = 0.41$

Generally the null hypothesis is $H_o : p \le 0.411$

The above condition represents the null hypothesis because it contains and equality in its condition

The alternative hypothesis is $H_a : \mu > 0.41$

6 0

3 years ago