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Inessa05 [86]
3 years ago
9

How many lines of symmetry does this figure have

Mathematics
1 answer:
kondor19780726 [428]3 years ago
6 0

Answer:

2

Step-by-step explanation:

ot like you fold a paper

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Help please:):(“/$)
Andrews [41]

1. Distance between points is 7

2. Distance between points is 6

3. Distance between points is 10

4. Distance between points is 6

5. Distance between points is 4

4 0
3 years ago
Draw a quadrilateral with one pair of parallel sides and two right angles. Explain why this figure is a trapezoid.
Jlenok [28]

Answer:i cant draw on brainly

Step-by-step explanation:i cant draw

6 0
3 years ago
Find the x-values (if any) at which f is not continuous. which of the discontinuities are removable? (use k as an arbitrary inte
stich3 [128]

Here we are to find the values of x in which the function f (x) = csc 5x is discontinuous. What this usually means is to find when the value approaches infinity.

 

We know from trigonometric identities that csc is the equivalent to 1 / sin, therefore the function in terms of sin is:

f(x) = 1 / sin 5x

 

We can see that the function becomes discontinuous when sin 5x = 0, that is a value divided by 0 is discontinuous or approaches infinity.

 

sin 5x is equal to zero when:

5x = 0 or π

So given k as an arbitrary integer

5x = k π

So k can be: k = 0, 1, 2

x = k π/ 5 

6 0
3 years ago
Write the equation of a line that is perpendicular to y = 7/5 x + 6 y= 5/7and that passes through the point ( 2 , − 6 )
Margarita [4]

<u>Answer</u>:

Equation of a line perpendicular toy = \frac{7}{5x} + 6 and passes through the point ( 2 , − 6 ) is   5x – 7y = 4.

<u>Explanation</u>:

Need to write equation of line perpendicular  to y = 7/5x + 6 and passes through the point ( 2 , − 6 )

Generic slope intercept form of a line is given by y = mx + c , where m = slope of the line.

On comparing the given slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line y = \frac{7}{5}x + 6, slope m = 7/5

Product of slope of perpendicular line is -1 .

Let say slope of required line perpendicular to y = 7/5x + 6 is represented by m1  

And as Product of slope of perpendicular line is -1 .

=> m \times m1 = -1

=>\frac{7}{5}\times m1 = -1

=>m1 = \frac{-5}{7}

so now we  need to find the equation of a line whose slope is \frac{-5}{7} and passing through (2 , -6).

Equation of line passing through (x1 , y1)  and having slope of m is given by  

(y – y1) = m (x – x1)

In our case x1 = 2 and  y1 = -6  and m = -5/7  

Substituting the values in equation of line we get

=>  (y-(-6)) = \frac{-5}{7} (x-2)

=>y +6= \frac{-5}{7} x + \frac{10}{7}

=> 7(y +6) = -5x +10

=> 5x – 7y = 10 – 6

=> 5x – 7y = 4  

Hence equation of a line perpendicular toy = \frac{7}{5x} + 6  and passes through the point ( 2 , − 6 ) is  

5x – 7y = 4.

8 0
3 years ago
Chris ran 3 miles in 15 minutes and continues to run at this rate for 1 hour. Amy ran 4 miles in
kiruha [24]

Answer:  

the ans is in the picture  

Amy ran farthest in one hour

Step-by-step explanation:

(hope it helps can i plz have brainlist :D hehe)

6 0
3 years ago
Read 2 more answers
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