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2 years ago

Please answer correctly !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Digiron [165]2 years ago

8 0

Answer:

Okayy

Step-by-step explanation:

Since T is the centroid which is the center

Also T is a midpoint

Nt=tn=42

Hope this helps

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I have a limited time please help ;-;

diamong [38]

Jessica saves $4 more a week than Raphael. I took this quiz and it was correct.

6 0

2 years ago

Read 2 more answers

ZA and ZB are supplementary angles. If mZA = (5x + 25)° and m

liberstina [14]

Answer:

MZA = 140

Step-by-step explanation:

5x+25°+ x + 17°=180°(Supplimentary Angles)

6x + 42° =180°

6x =180 - 42

6x=138

(divide by 6 both sides)

X= 23

substitution X into the given angle

5x +25

5(23)+25

115+25

140

3 0

2 years ago

Need help! Does anyone know how to do this type of math? (It's geometry)

mart [117]

Answer:

Step-by-step explanation:

refer the attachment

to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that tangents which meet at the same point are equal that is being said

FA=AI=17
CH=CG=2.5

since $\rm BA=FA+FB$ and it's given that FA and BA are 17 and 29 FB should be

$\rm 29=17+FB$

therefore,

$FB=29-17=\boxed{12}$

once again by two tangent theorem we acquire:

$FB=BH=\boxed{12}$

As BC=BH+CH,BC is

12+2.5
$\boxed{14.5}$

likewise,AD=AI+DI so,

21=17+DI [AD=21(given) and AI=17 (by the theorem)]

thus,

DI=21-17= $\boxed{4}$

By the theorem we obtain:

DI=DG=4

Similarly,DC=DG+CH therefore,

DC=4+2.5= $\boxed{6.5}$

Now finding the Perimeter of ABCD

$P_{\text{ABCD}}=\text{AB+AD+BC+DC}$

substitute what we have and got

$P_{\text{ABCD}}=\text{29+21+14.5+6.5}$

simplify addition:

$P_{\text{ABCD}}=\boxed{71}$

hence,

the Perimeter of ABCD is 71

4 0

2 years ago

What fraction is at the same location as 1/4

Maksim231197 [3]

Answer:

Fractions equivalent to 1/4 are 2/8, 3/12, 4/16, 5/20, 6/24, 7/28, 8/32, 9/36, 10/40.

those are the ones i know so far

3 0

3 years ago

The hypotenuse of a right triangle is 7 inches,and one of the legs is 13 inches.Find the length of the other leg.

Firlakuza [10]

$13^{2} plus b^{2} =7^{2} 

169 plus b^{2} = 49
$

6 0

3 years ago