All categories

3 years ago

Multiple (7s^5)(-1/5s^3

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

8 0

Answer:

Is that a real equation?

Step-by-step explanation:

You might be interested in

F(x)=3x-5 and g(x)=2x+5 What is f(x) - g(x), and another problem.

prohojiy [21]

here are the steps hope it helps

5 0

3 years ago

What is x + 15 > 3?

Over [174]

Answer:

hmm

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find the surface of the triangular prism

svetoff [14.1K]

Answer:

Step-by-step explanation:

6²+8²=36+64=100=10²

so it is a right angled triangular prism.

surface area=2×(1/2 ×8×6)+(6+8+10)×7

=48+980

=1028 sq. m.

8 0

3 years ago

Read 2 more answers

solve the equation using the Quadratic Formula. Round your solutions to the nearest tenth if necessary.) please help I need expl

Viefleur [7K]

Answer:

Quadratic Formula x = [-b +- Sq root (b^2 - 4ac)] / 2a

In this example a= 2 b= -6 c= 5

x = [- - 6 +- Sq root ((-6^2) - 4 *2*5)] / 2*2

x = [6 +-sq root (36 -40)] / 4

x = 6 +- 2i / 4

x1 = 1.5 + .5i

x2 = 1.5 -.5i

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

30 POINTS! Consider the system of linear equations and the matrix equations below.

fiasKO [112]

Answer:

Option C is correct.

Step-by-step explanation:

-x+3y=2

4x-2y=22

In matrix form is represented as:

$\left[\begin{array}{cc}-1&3\\4&-2\end{array}\right] \left[\begin{array}{c}x&y\end{array}\right] =\left[\begin{array}{c}2&22\end{array}\right]$

AX=B

$X = A^{-1}B$

$A^{-1} = |A|/Adj A$

|A| = (-1)(-2)-(3)(4)

|A| = 2-12

|A| = -10

Adj A = $\left[\begin{array}{cc}-2&-3\\-4&-1\end{array}\right]$

A^-1 = -1/10 $\left[\begin{array}{cc}-2&-3\\-4&-1\end{array}\right]$

A^-1 = 1/10 $\left[\begin{array}{cc}2&3\\4&1\end{array}\right]$

X= A^-1 B

X = 1/10 $\left[\begin{array}{cc}2&3\\4&1\end{array}\right]$ $\left[\begin{array}{c}2&22\end{array}\right]$

X=1/10 $X=1/10\left[\begin{array}{c}2*2+3*22\\4*2+1*22\end{array}\right]\\X=1/10\left[\begin{array}{c}4+66\\8+22\end{array}\right]\\X=1/10\left[\begin{array}{c}70\\30\end{array}\right]\\X=\left[\begin{array}{c}70/10\\30/10\end{array}\right]\\X=\left[\begin{array}{c}7\\3\end{array}\right]$

So, x = 7 and y =3

Hence Option C is correct.

4 0

3 years ago

Read 2 more answers

Multiple (7s^5)(-1/5s^3​

Multiple (7s^5)(-1/5s^3