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yawa3891 [41]
2 years ago
14

A train is moving at a uniform speed of 75 km/hour.

Mathematics
2 answers:
SIZIF [17.4K]2 years ago
5 0

Answer:

25km; 200 minutes (3h20m)

Step-by-step explanation:

20 minutes is 1/3 of an hour. If it travels 75km in one, it will travel 1/3 of the distance in 20 minutes. or 25 km.

Conveniently, 250 km is 10 times the distance it travels in 20 minutes. As long as it maintains its speed. it will take 10 times 20 minutes, or 200 minutes (that's 3 hours, 20 minutes)

natulia [17]2 years ago
4 0

→ Let the distance travelled (in km) in 20 mins be (x) and time taken (in mins) to cover 250km be y.

As we know , ( 1 hour = 60 minutes ) .

• Distance travelled (in km) = 75 , x , 250.

• Distance travelled (in mins) = 60 , 20 , y .

→ Since the speed is uniform , Therefore , The distance covered would be directly proportional to time .

<h3><u>Solution (I) :</u></h3>

• We have ;

\frac{75}{60}  =  \frac{x}{20}

\frac{75}{60}  \times 20 = x

x = 25

So , the train will cover a distance of 25km in 20 minutes...

<h3><u>Solution (II) : </u></h3>

• Also ;

\frac{75}{60}  =  \frac{250}{y}

y =  \frac{250 \times 60}{75}  = 200 \: mins \:

→ 200 mins , 3 hrs , 20 mins

Therefore , 3 hours 20 minutes will be required to cover a distance of 250 kilometres.

→ Alternatively , When x is known , Then one can determine y from the relation ;

=  >  \frac{x}{20}  =  \frac{250}{y}

<h3><u>Additional Information :- </u></h3>

→ You know that a map is a miniature representation of a very large region .

→ A scale is usually given at the bottom of the map. The scale shows a relationship between actual length and the length represented on the map .

→ The scale of the map is thus the ratio of the distance between two points on the map to the actual distance between two points on the large region .

→ For example :- If 1 cm on the map represents 8km of actual distance [ i.e., the scale is 1cm : 8km or 1 : 800,000 ] then 2cm on the same map will represent 16km. Hence , We can say that scale of a map is based on the concept of direct proportion...

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