Answer:
A. 7,348
Step-by-step explanation:
P = le^kt
intitial population = 500
time = 4 hrs
end population = 3,000
So we have all these variables and we need to solve for what the end population will be if we change the time to 6 hours. First, we need to find the rate of the growth(k) so we can plug it back in. The given formula shows a exponencial growth formula. (A = Pe^rt) A is end amount, P is start amount, e is a constant that you can probably find on your graphing calculator, r is the rate, and t is time.
A = Pe^rt
3,000 = 500e^r4
now we can solve for r
divide both sides by 500
6 = e^r4
now because the variable is in the exponent, we have to use a log
ln(6) = 4r
we can plug the log into a calculator to get
1.79 = 4r
divide both sides by 4
r = .448
now lets plug it back in
A = 500e^(.448)(6 hrs)
A = 7351.12
This is closest to answer A. 7,348
8/11 cant be an improper fraction because the numerator is smaller than the denominator
Answer:
Yes, F is a continuous function of r
Step-by-step explanation:
We are given that
When r<R
Where M=Mass of the earth
R=Radius of earth
G=Gravitational constant
We have to find the function is continuous of r or not.
LHL
RHL
When a function is continuous at x=a
Then, LHL=RHL=f(a)
RHL==LHL=F(R)
Hence, the function is continuous of r.
Answer:
5(a+4)
Step-by-step explanation:
expression is equivalent to 5a+20
To get the equivalent expression we need to factor the given expression
5a+ 20
5a can be written as 5 * a
20 can be written as 5*2*2
WE can see that common factor is 5 for both 5a and 20
So GCF is 5
Now we factor out GCF 5
WE put 5 outside and write all the left of factors inside the parenthesis
5a +20
5 (a+2*2)
5(a+4)