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PolarNik [594]
2 years ago
10

If a figure has been dilated by a scale factor of one third, which transformation could be used to prove the figures are similar

using the AA similarity postulate? A translation because it can map one angle onto another since dilations preserve angle measures of triangles. A rotation because it can change the orientation of a figure since dilations do not preserve orientation. A dilation because it can map one side onto another since dilations preserve side length of triangles. A reflection because it can change the orientation of a figure since dilations do not preserve orientation.
Mathematics
2 answers:
uysha [10]2 years ago
5 0

Answer:

A translation can map one angle onto another since dilations preserve angle measures of triangles.

Step-by-step explanation:

dezoksy [38]2 years ago
5 0

Answer:

the answer is b

Step-by-step explanation:

took the test

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Answer:

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Step-by-step explanation:

The equation to solve is:

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To get rid of the "square", we need to take square root of both sides:

\sqrt{(x+\frac{1}{2})^2}=\sqrt{\frac{4}{9}}\\x+\frac{1}{2}=\frac{\sqrt{4}}{\sqrt{9}}

Then we use algebra to find the value(s) of x. Remember, when we take square root, we have to add up a "+-" (on the right side). Shown below:

x+\frac{1}{2}=+-\frac{\sqrt{4}}{\sqrt{9}}\\x+\frac{1}{2}=+-\frac{2}{3}\\x=\frac{2}{3}-\frac{1}{2}=\frac{1}{6}\\x=-\frac{2}{3}-\frac{1}{2}=-\frac{7}{6}

So these are 2 answers for x.

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3 years ago
What is the period of y=3cot(4x−3π)
Stells [14]
Hello!

hint: we can rewrite your function as below:

<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π = 

=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)

</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:

<span>"4P=π"


Hope this Helps! Have A Wonderful Day! :)</span>
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Step-by-step explanation:

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The Correct graph is fourth one !

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