Un decimal que es 1/10 de 3,0 es 0,3
Given that the function g(x)=x-3/x+4, the evaluation gives:
- g(9) = 6/13.
- g(3) = 0.
- g(-4) = undefined.
- g(-18.75) = 1.07.
- g(x+h) = x+h-3/x+h+4
<h3>How to evaluate the function?</h3>
In this exercise, you're required to determine the value of the function g at different intervals. Thus, we would substitute the given value into the function and then evaluate as follows:
When g = 9, we have:
g(x)=x-3/x+4
g(9) = 9-3/9+4
g(9) = 6/13.
When g = 3, we have:
g(x)=x-3/x+4
g(3) = 3-3/3+4
g(3) = 0/13.
g(3) = 0.
When g = -4, we have:
g(x)=x-3/x+4
g(-4) = -4-3/-4+4
g(-4) = -1/0.
g(-4) = undefined.
When g = -18.75, we have:
g(x)=x-3/x+4
g(-18.75) = -18.75-3/-18.75+4
g(-18.75) = -15.75/-14.75.
g(-18.75) = 1.07.
When g = x+h, we have:
g(x)=x-3/x+4
g(x+h) = x+h-3/x+h+4
Read more on function here: brainly.com/question/17610972
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Properties of Logs
logb(x/y) = log<span>bx</span> - log<span>by</span>.
therefore
log5 (4/7)= log5 (4)- log5 (7)
<span>Solve log 5 (4) and log 5 (7) with the base change of the logarithm</span>
<span>log 5 4 = log 4 / log 5 </span>
Use the calculator:
<span>
<span>log 5 4 =0.8613531161
</span></span>
log 5 7 = log 7 / log 5
<span>log 5 7 =1.2090619551</span>
<span>log5 (4/7)= log5
(4)- log5 (7)=-0.347708839</span>
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Answer:
1
Step-by-step explanation: