Answer:
The quantity of acid in the solution is 47.1 ml
Step-by-step explanation:
Given as :
The quantity of solution of acid and water = 357 millimeters
The percentage of acid in the solution = 13.2 %
Let the quantity of acid in the solution = x ml
<u>So, According to question </u>
13.2 % of the total quantity of acid in the solution = x
I.e x = 13.2 % × 357
Or, x = 
× 357
Or, x = 0.132 × 357
∴ x = 47.124 millimeters
So , The quantity of acid = 47.1 ml
Hence The quantity of acid in the solution is 47.124 ml Answer
Answer:
165 combinations possible
Step-by-step explanation:
This is a combination problem as opposed to a permutation, because the order in which we fill these positions is not important. We are merely looking for how many ways each of these 11 people can be rearranged and matched up with different candidates, each in a different position each time. The formula can be filled in as follows:
₁₁C₃ = 
which simplifies to
₁₁C₃ = 
The factorial of 8 will cancel out in the numerator and the denominator, leaving you with
₁₁C₃ = 
which is 165
Cosine law
a²=b²+c²-2ab*cosA
a²=13²+11²-2*13*11*cos(108)≈378.37
a≈19.45
Answer:
A)12 square units
The wavefunction for a particle in a one-dimension box is a well-known problem, which has as a solution:
Ψ(x) = √(2/l) sin (nπx/l)
When the box has three dimensions, the general solution is simply the multiplication of the solutions for each dimension, therefore:
Ψ(x) = K · sin (n_x·π·x / l) · sin (n_y·π·y / l) · sin <span>(n_z·π·z / l)</span>
