1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Inessa05 [86]
3 years ago
13

Evaluate-2.75 - f for f = -6.5

Mathematics
1 answer:
Stels [109]3 years ago
4 0

Answer:

Step-by-step explanation:

we have f=-6.5

-2.75- (-6.5)= -2.75+6.5=3.75

You might be interested in
Annalee hammered in nail into a piece of wood each time she hammer the nail it went to 1/8 Inch deeper into the word if she hamm
mash [69]

Answer: 0.5 inch

Step-by-step explanation:

Given

On hammering nail advances \frac{1}{8}\ inch  each time

Annalee hammered 4 times

So, total advancement of nail= 4\times \dfrac{1}{8}=\dfrac{1}{2}\ inch

3 0
2 years ago
A cheetah can run at its top speed for about 25 seconds. Complete the table to represent a cheetah running at a constant speed.
AleksandrR [38]
X = 650 + 60t

The cheetah must arrive at the same place at the same time:

x = 90t

650 + 60t = 90t

30t = 650

t = 650/30 ≅ 21.7 s

It takes the cheetah a little more than 20 s running at 90 ft/s to reach the moving antelope, so assuming the antelope can maintain its speed of 60, it is safe.
5 0
3 years ago
The area of a rectangle is 70 m², and the length of the rectangle is 11 m less than three times the width. Find the dimensions o
11111nata11111 [884]

Step-by-step explanation:

the area of a rectangle is

length × width

in our case

length × width = 70 m²

length = 3×width - 11

we can use this second equation in the first and get

(3×width - 11) × width = 70

3×width² - 11×width - 70 = 0

the general solution to a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 3

b = -11

c = -70

x = (11 ± sqrt((-11)² - 4×3×-70))/(2×3) =

= (11 ± sqrt(121 + 840))/6 =

= (11 ± sqrt(961))/6

x1 = (11 + 31)/6 = 42/6 = 7

x2 = (11 - 31)/6 = -20/6 = -10/3

the negative solution is not applicable for a length in an object.

so, only x1 = 7 m is our solution.

the width of the rectangle is 7 m.

the length = 3×width - 11 = 3×7 - 11 = 21-11 = 10 m

7 0
2 years ago
At a certain concert, 73 % of the audience was under 20 years old. A random sample of n = 146 members of the audience was select
Tatiana [17]

Answer:  p = 0.73

Step-by-step explanation:

Given that,

73% of the audience was under 20 years old :

so, probability (p) = 0.73

n = 146

Mean of the distribution of sample proportion = ?

According to central limit theorem,

np(1-p) ≥ 10

146 × 0.73(0.27) ≥ 10

28.77 ≥ 10

∴ Central limit theorem assumes that the sample distribution of the sample proportion is normally distributed.

Hence, the mean of the distribution of sample proportion:

μ = p = 0.73

4 0
3 years ago
What is the quotient of 1.876 x 10^2 and 6.7 x 10^2 expressed in scientific notation?
neonofarm [45]

Answer:

345600000000 and 670

Step-by-step explanation:

6 0
3 years ago
Other questions:
  • 10 POINTS!.A sculptor is planning to make two triangular prisms out of steel. The sculptor will use △ABC for the bases of one pr
    13·1 answer
  • One end of a line segment has the coordinates (-6,2). If
    14·1 answer
  • There are 21 students  in Mr.Tentlers  class The students divided themselves evenly  into 3 groups.how many  students  are in ea
    10·2 answers
  • Can someone help me with this:
    13·1 answer
  • Slope = 1/6; (-12,-2)
    11·1 answer
  • You and your brother are reading the same novel. You want to get ahead of him in the book, so you decide to read 303030 minutes
    9·2 answers
  • What expression represents the profit, and what is the profit if 240 cell phones are sold?
    8·1 answer
  • Help me out? :) <br><br> don't guess, if u dont know just dont answer. NO LINKS.
    8·1 answer
  • Factor the expression below.
    10·1 answer
  • 3z+8=20<br> Answer <br> 4<br> 10<br> 8<br> 13
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!