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kiruha [24]
3 years ago
7

HenCe.

Mathematics
2 answers:
Nana76 [90]3 years ago
8 0

Answer:

34

Step-by-step explanation:

that what i think

NARA [144]3 years ago
7 0

Answer:

hmmm

Step-by-step explanation:

okay so taco cost 2.40 and birrito costin something idek im lazyyyyy but okie

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Please help I will give Brainliest please!
WITCHER [35]

Part (a)

The domain is the set of allowed x inputs of a function.

The graph shows that x = 0 is not allowed because of the vertical asymptote located here. It seems like any other x value is fine though.

<h3>Domain: set of all real numbers but x \ne 0</h3>

To write this in interval notation, we can say (-\infty, 0) \cup (0, \infty) which is the result of poking a hole at 0 on the real number line.

--------------

The range deals with the y values. The graph makes it seem like it stretches on forever in both up and down directions. If this is the case, then the range is the set of all real numbers.

<h3>Range: Set of all real numbers</h3>

In interval notation, we would say (-\infty, \infty) which is almost identical to the interval notation of the domain, except this time of course we aren't poking at hole at 0.

=======================================================

Part (b)

<h3>The x intercepts are x = -4 and x = 4</h3>

We can compact that to the notation x = \pm 4

These are the locations where the blue hyperbolic curve crosses the x axis.

=======================================================

Part (c)

<h3>Answer: There aren't any horizontal asymptotes in this graph.</h3>

Reason: The presence of an oblique asymptote cancels out any potential for a horizontal asymptote.

=======================================================

Part (d)

The vertical asymptote is located at x = 0, so the equation of the vertical asymptote is naturally x = 0. Every point on the vertical dashed line has an x coordinate of zero. The y coordinate can be anything you want.

<h3>Answer: x = 0 is the vertical asymptote</h3>

=======================================================

Part (e)

The oblique or slant asymptote is the diagonal dashed line.

It goes through (0,0) and (2,6)

The equation of the line through those points is y = 3x

If you were to zoom out on the graph (if possible), then you should notice the branches of the hyperbola stretch forever upward but they slowly should approach the "fencing" that is y = 3x. The same goes for the vertical asymptote as well of course.

<h3>Answer:  Oblique asymptote is y = 3x</h3>
5 0
3 years ago
One angle of a right triangle measures 80 degrees. what is the measure of the other acute angle
Tanya [424]

Answer:

10 degrees

Step-by-step explanation:

Since a right angle is 90 degrees in total, to find the missing degree subtract 80 from 90.

90-80=10 degrees

<u><em>Hope this helps </em></u>

3 0
3 years ago
I need some help please
Natasha2012 [34]

Answer:

2 circles :8 triangles

Step-by-step explanation:

just count the circles than the triangles

7 0
3 years ago
Read 2 more answers
In ΔDEF, the measure of ∠F=90°, DE = 8.8 feet, and EF = 6.4 feet. Find the measure of ∠D to the nearest tenth of a degree.
creativ13 [48]

Answer:

46.7 degrees.

Step-by-step explanation:

According to the given information, triangle DEF is a right triangle with angle F as the right angle. We are trying to find the measure of angle D.

We are given the opposite side length (6.4 feet) and the hypotenuse (8.8 feet), so we can use sine to calculate the angle measure (SOH = Sine; Opposite over Hypotenuse).

sin(D) = 6.4 / 8.8

sin(D) = 64 / 88

sin(D) = 8 / 11

D = arcsin(8 / 11)

D = arcsin(0.72727272727272727272727273)

D = 46.65824177.

So, the measure of angle D is about 46.7 degrees.

Hope this helps!

4 0
3 years ago
Use the zero product property to find the solutions to the equation x^2-13x+30=0
Daniel [21]

We need to solve the zeroes of the given expression x² - 13x + 30 = 0 and we need to apply zero product property.First, we need to identify the two numbers which will result to -13 when added and it will result to 30 when multiplied. These two numbers are -3 and -10. Then, we can proceed with the solution such as:
x² - 13x + 30 = 0
(x-3) (x- 10) =0
From above, we have already the two zero product:
x-3 = 0
x1 = 3
x-10 =0
x2 =10

The answers are x1 = 3 and x2 = 10.
8 0
4 years ago
Read 2 more answers
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