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Rashid [163]
3 years ago
5

(3b)^2c when b=3 and c=7

Mathematics
2 answers:
fredd [130]3 years ago
7 0
<span>(3b)^2c when b=3 and c=7

(3 * 3)^2 * 7
= (3^2)^2 * 7
= 3^4 * 7
= 81 * 7
= 567</span>
erik [133]3 years ago
3 0
567 becaue 3x3=9 and 9^2x7= 567
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Given problem is 3x-4+2(x-5)=9x+8-2x

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