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fiasKO [112]
3 years ago
12

Hi, I'm confused by this wording, thanks.

Mathematics
1 answer:
Margarita [4]3 years ago
5 0

Answer:

So i can't do it because this is a test

Step-by-step explanation:

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Find the value of y.
BaLLatris [955]
2x + 10 and x + 40 are vertical angles.  By definition, vertical angles are congruent.  So let's take care of that first. 2x+10 = x+40.  Subtract an x from both sides and at the same time subtract 10 from both sides to get x = 30.  Ok so x = 30.  So what, right?  We need y.  Well, 2y+x is vertical with an angle that has the exact same measure as 2y+x because vertical angles are congruent.  We know that all those angles add up to equal 360, so here's our equation: 2x+10+x+40+2y+x+2y+x=360.  Combining like terms gives us 5x+4y=360.   We already have a value for x, remember, so we will sub it in.  x=30.  5(30)+4y=360  and  150 + 4y = 360.  Subtract 150 from both sides and we have 4y = 210.  Divide both sides by 4 to get that y = 52.5.  There you go!
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A family of 8 mice move into your barn. After 3 months, there are now 51 mice. At 8 months, how many mice will you have in your
balu736 [363]
Well, there would be 136 mice in the barn
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3 years ago
How do you describe the graph
Andrews [41]

http://www.stgeorges.co.uk/blog/how-can-i-describe-a-graph-ielts-writing-task-part-1-business-english

7 0
3 years ago
Find the coordinates of the intersection of the diagonals of parallelogram HJKL with the given vertices: H(-1, 4), J(3, 3), K(3,
lakkis [162]

Answer:

(1, 1)

Step-by-step explanation:

Given vertices of the <u>parallelogram</u>:

  • H = (-1, 4)
  • J = (3, 3)
  • K = (3, -2)
  • L = (-1, -1)

Therefore the <u>parallel sides</u> are:

\sf \overline{HJ} \parallel \overline{LK}\:\: \textsf{ and }\:\: \overline{LK} \parallel \overline{HL}

Therefore, the <u>diagonals</u> of the parallelogram are:

\sf \overline{LJ} \:\: \textsf{ and }\:\:\overline{HK}

To find the <u>coordinates of the intersection of the diagonals</u>, either:

  1. draw a diagram (see attached) and determine the point of intersection of the diagonals from the diagram, or
  2. determine the midpoint of either diagonal (as the diagonals of a parallelogram bisect each other, i.e. divide into 2 equal parts).

<u>Midpoint between two points</u>

\textsf{Midpoint}=\left(\dfrac{x_2+x_1}{2},\dfrac{y_2+y_1}{2}\right)\quad \textsf{where}\:(x_1,y_1)\:\textsf{and}\:(x_2,y_2)\:\textsf{are the endpoints}}\right)

To find the <u>midpoint of diagonal LJ</u>, define the endpoints:

  • (x_1,y_1)=L=(-1, -1)
  • (x_2,y_2)=J=(3,3)

Substitute the defined endpoints into the formula and solve:

\begin{aligned} \implies \textsf{Midpoint of LJ} & =\left(\dfrac{3-1}{2},\dfrac{3-1}{2}\right)\\ & =\left(\dfrac{2}{2},\dfrac{2}{2}\right)\\ & =\left(1,1\right) \end{aligned}

Therefore, the coordinates off the intersection of the diagonals of parallelogram HJKL are (1, 1).

Learn more about midpoints here:

brainly.com/question/27962681

8 0
2 years ago
Read 2 more answers
HELP PLEASE<br><br> Which of the following graphs is not a function
Luden [163]
A simple rule to tell whether a graph is a function is to pretend to cut it vertically, if any cut intercept the graph twice, it is not a function. otherwise, it is. 
In this case, the heart is not a function, because if you cut it up-down direction, your imaginary knife will touch the edge of the heart twice.
I hope this explanation helps.<span />
3 0
3 years ago
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