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3 years ago

The sum of 3x^2+4x-2 and x^2-5x+3 is

Mathematics

2 answers:

Charra [1.4K]3 years ago

6 0

4x² - x + 1

summing gives :

3x² + 4x - 2 + x² - 5x + 3 ( collect like terms )

(3x² + x² ) + (4x - 5x ) + ( - 2 + 3 )

= 4x² - x + 1

Diano4ka-milaya [45]3 years ago

3 0

The sum would be

4x^2-x+1

add like terms.

3x^2+x^2

4x^2

4x+-5x

-x

3-2

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The vertices of a right triangle are (–6, 4), (0, 0), and (x, 0). Find the value of x.

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3 years ago

A deck of 38 cards contains 16 blue cards, 6 red cards, and 16 yellow cards. What is the probability of randomly drawing a blue

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The probability of drawing a blue card is equal to the quotient when the number of blue cards is divided by the total number of cards. This is, 16/38 which is also equal to 8/19. Thus, the probability of drawing a yellow card is 8/19. The answer is letter C.

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3 years ago

Help please this is for my homework that is due to tomorrow!!

Murljashka [212]

The given polygons are similar

Step-by-step explanation:

By observing the given diagrams, we can see that the respective angles are congruent.

Two shapes are said to be similar if they have same shapes or one shape is created by uniformly increasing or decreasing the side of other.

For this purpose we find the scale factor of greater to smaller image, if the scale factor is same for each side then the two shapes are similar

So,

The scale factor is:

$\frac{EF}{AB} = \frac{3}{1} = 3\\\\\frac{FG}{BC} = \frac{9}{3} = 3\\\\\frac{GH}{CD} = \frac{15}{5} = 3\\\\\frac{EH}{AD} = \frac{21}{7} = 3$

We can see that the scale factor is same for all sides.

Hence,

The given polygons are similar

Keywords: Polygons, similarity

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2 years ago

3x+8x(-8x+3)= simplify it i guess

xxMikexx [17]

Answer:

27x-64x^2

Step-by-step explanation:

Distribute the 8x

3x-64x^2+24x

Combine like terms (3x and 24x)

27x-64x^2

6 0

3 years ago

Read 2 more answers

AABC has vertices at A(1, -9), B(8,0), and C(9,-8).

Rainbow [258]

Check the picture below.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-9})\qquad B(\stackrel{x_2}{8}~,~\stackrel{y_2}{0}) ~\hfill AB=\sqrt{[ 8- 1]^2 + [ 0- (-9)]^2} \\\\\\ AB=\sqrt{7^2+(0+9)^2}\implies AB=\sqrt{7^2+9^2}\implies \boxed{AB=\sqrt{130}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{8}~,~\stackrel{y_1}{0})\qquad C(\stackrel{x_2}{9}~,~\stackrel{y_2}{-8}) ~\hfill BC=\sqrt{[ 9- 8]^2 + [ -8- 0]^2} \\\\\\ BC=\sqrt{1^2+(-8)^2}\implies \boxed{BC=\sqrt{65}}$

now, we could check for the CA distance, however, we already know that AB ≠ BC, so there's no need.

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2 years ago