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White raven [17]
3 years ago
9

Kevin drove 693 miles in 11 hours. At the same rate, how many miles would he drive in 9 hours

Mathematics
2 answers:
rodikova [14]3 years ago
5 0

Answer:

567 Miles

Step-by-step explanation:

pochemuha3 years ago
5 0

Answer:

567 mi

Step-by-step explanation:

you have to divide by 11 then multiply by 9

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just olya [345]

Yes you are correct 20% of 150 is 30.

3 0
3 years ago
Read 2 more answers
The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0
3 years ago
A festival charges $3 for child admission and $5 for adult admision. At the end of the festival they have sold 779 tickets for a
lutik1710 [3]

Answer:

562 child tickets were sold

217 adult tickets were sold

Step-by-step explanation:

A festival charges $3 for children admission and $5 for adult admission

At the end of the festival they have sold a total number of 779 tickets for $2771

Let x represent the child ticket

Let y represent the adult ticket

x + y= 779..............equation 1

3x + 5y= 2771..........equation 2

From equation 1

x + y = 779

x= 779 -y

Substitute 779-y for x in equation 2

3x + 5y= 2771

3(779-y) + 5y= 2771

2337 - 3y + 5y= 2771

2337 +2y= 2771

2y= 2771 -2337

2y = 434

y = 434/2

y = 217

Substitute 217 for y in equation 1

x + y= 779

x + 217= 779

x = 779-217

x= 562

Hence 562 child tickets were sold and 217 adult tickets were sold

6 0
3 years ago
What is the volume of the composite figure? Express the answer in terms of pie.
zhenek [66]

Answer:

3127 mm3

Step-by-step explanation:

3 0
3 years ago
2(n+5)=-2 step by step plz
Elodia [21]

Answer:

n=-6

Step-by-step explanation:

2(n+5)=-2

distribute

2(n+5)

2xn 2x5

2n+10

2n+10=-2

subtract 10 from both sides

10-10=0

-2-10=-12

2n=-12

divide each side by 2

2n/2=n

-12/2=-6

n=-6

6 0
3 years ago
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