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3 years ago

Find the measure of angle A

Mathematics

2 answers:

Otrada [13]3 years ago

6 0

Answer:

The measure of angle A is 30 degrees.

Step-by-step explanation:

Since all triangles are equal to 180 degrees, you take set up an equation where u add 2x and 3x to get 5x and u add that to 130 and set it equal to 180

2x+3x+130=180 ( combine like terms)

5x=50 (subtract 130 from both sides to isolate our variable which is x)

x=10 (divide both sides by 5 to get rid completly isolate our variable)

Now we know x=10 you can plug that in as our x value so 3x becomes 3*10 which equals 30 which is your answer.

Nataly [62]3 years ago

4 0

Answer:

so 2x+3x+130=180

so 5x+130=180

5x=50

so 2x =20

3x which is angle a is equal to 30 degree

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In right △ABC, the altitude CH to the hypotenuse AB intersects angle bisector AL in point D. Find the sides of △ABC if AD = 8 cm

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Answer:

$AC=8\sqrt{3}\ cm\\ \\AB=16\sqrt{3}\ cm\\ \\BC=24\ cm$

Step-by-step explanation:

Consider right triangle ADH ( it is right triangle, because CH is the altitude). In this triangle, the hypotenuse AD = 8 cm and the leg DH = 4 cm. If the leg is half of the hypotenuse, then the opposite to this leg angle is equal to 30°.

By the Pythagorean theorem,

$AD^2=AH^2+DH^2\\ \\8^2=AH^2+4^2\\ \\AH^2=64-16=48\\ \\AH=\sqrt{48}=4\sqrt{3}\ cm$

AL is angle A bisector, then angle A is 60°. Use the angle's bisector property:

$\dfrac{CA}{CD}=\dfrac{AH}{HD}\\ \\\dfrac{CA}{CD}=\dfrac{4\sqrt{3}}{4}=\sqrt{3}\Rightarrow CA=\sqrt{3}CD$

Consider right triangle CAH.By the Pythagorean theorem,

$CA^2=CH^2+AH^2\\ \\(\sqrt{3}CD)^2=(CD+4)^2+(4\sqrt{3})^2\\ \\3CD^2=CD^2+8CD+16+48\\ \\2CD^2-8CD-64=0\\ \\CD^2-4CD-32=0\\ \\D=(-4)^2-4\cdot 1\cdot (-32)=16+128=144\\ \\CD_{1,2}=\dfrac{-(-4)\pm\sqrt{144}}{2\cdot 1}=\dfrac{4\pm 12}{2}=-4,\ 8$